The speed of the coin is 31.765 m/s when it falls 20 m below the person
Further Explanation
Initially, the coin is thrown with the speed of 15m/s upwards.
When coming down the coin will have the same speed of 15 m/s in a downward direction.
Therefore, in diagram;
Normally,
S = distance = m
v = speed = m / s
t = time = seconds
acceleration due to gravity = g = 9.8 m/s²
and in this case;
u = 15 m/s
h = d = 60 m – 20 m = 40 m (this is because, when the coin is 20 m underneath the person it is 40 m above the ground)
V =?
We know that, V2 = u2 + 2gh
V² = 15² + (2×9.8×40)
= 225 + 784
= 1009
V = √1009
V = 31.765 m/s
NB. Acceleration due to gravity can also be 10 m/s² instead of 9.8 m/s
The speed of the coin is 31.765 m/s when it falls 20 m below the person
Further Explanation
Initially, the coin is thrown with the speed of 15m/s upwards.
When coming down the coin will have the same speed of 15 m/s in a downward direction.
Therefore, in diagram;
Normally,
S = distance = m
v = speed = m / s
t = time = seconds
acceleration due to gravity = g = 9.8 m/s²
and in this case;
u = 15 m/s
h = d = 60 m – 20 m = 40 m (this is because, when the coin is 20 m underneath the person it is 40 m above the ground)
V =?
We know that, V2 = u2 + 2gh
V² = 15² + (2×9.8×40)
= 225 + 784
= 1009
V = √1009
V = 31.765 m/s
NB. Acceleration due to gravity can also be 10 m/s² instead of 9.8 m/s
Answer Details:
Subject:physics
Level: high school
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