Answer:
If resistance increases current decreases.
Explanation:
- Current is <em>inversely proportional</em> to the resistance.
- from the relation given below, we can clearly see the relation between current and resistance;
V=IR
I ∝ 1/R
This relation shows that when resistance increases,current decreases.
mass of the bottle in each case is M = 0.250 kg
now as per given speeds we can use the formula of kinetic energy to find it
1) when speed is 2 m/s
kinetic energy is given as
![K = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![K = \frac{1}{2}(0.250)(2)^2 = 0.5 J](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%280.250%29%282%29%5E2%20%3D%200.5%20J)
2) when speed is 3 m/s
kinetic energy is given as
![K = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![K = \frac{1}{2}(0.250)(3)^2 = 1.125 J](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%280.250%29%283%29%5E2%20%3D%201.125%20J)
3) when speed is 4 m/s
kinetic energy is given as
![K = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![K = \frac{1}{2}(0.250)(4)^2 = 2 J](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%280.250%29%284%29%5E2%20%3D%202%20J)
4) when speed is 5 m/s
kinetic energy is given as
![K = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![K = \frac{1}{2}(0.250)(5)^2 = 3.125 J](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%280.250%29%285%29%5E2%20%3D%203.125%20J)
5) when speed is 6 m/s
kinetic energy is given as
![K = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![K = \frac{1}{2}(0.250)(6)^2 = 4.5 J](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%280.250%29%286%29%5E2%20%3D%204.5%20J)
Answer:
a) 4.40 s
b) 2.20 s
Explanation:
Given parameters are:
At constant power ,
initial speed of the car, ![v_0=0](https://tex.z-dn.net/?f=v_0%3D0)
final speed of the car,
mph
At full power,
initial speed of the car, ![v_0=0](https://tex.z-dn.net/?f=v_0%3D0)
final speed of the car,
mph
a)
At constant power, ![KE = \frac{1}{2} mv^2](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E2)
At full power, ![KE = \frac{1}{2} m(2v)^2](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%282v%29%5E2)
So ![KE_f = 4KE_i](https://tex.z-dn.net/?f=KE_f%20%3D%204KE_i)
So, time to reach 64 mph speed is 4 times more than the initial time
s
b)
![miles/hours^2](https://tex.z-dn.net/?f=miles%2Fhours%5E2)
For final 64 mph speed,
=
s
An object will stay in motion unless acted upon by an UNBALANCED force.
<h2>Answer: Transpiration
</h2>
Vegetal transpiration is the loss of water in the form of vapor, in the plant through its different parts, especially its leaves.
In this process, soil water is absorbed by the roots of the plant and transported in liquid form to the leaves to be converted into water vapor, while a part is used in photosynthesis. That is why vegetal transpiration is considered a vital function in the photosynthesis process.
This is possible because the leaves have small pores that allow water to escape into the atmosphere in the form of vapor and absorb carbon dioxide. Then, most of the water in the plants is used in the process of transpiration and only a small percentage is retained in liquid state and used for its growth and storage.