All categories

10 months ago

The bending of waves such as sound waves, light waves, and waves in water, around obstacles or the edges of openings is called.

Physics

1 answer:

kolezko [41]10 months ago

4 0

Answer:

Diffraction

Explanation:

Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.

You might be interested in

(50 Points) Need to know ASAP!! What human needs or desires were met through the development of alpaca populations??

alexira [117]

Alpacas were used for their meat, fibers for clothing, and art, and their images in the form of conopas.

8 0

3 years ago

A liquid of density 1200kg/m³ is filled in a beaker upto the depth of 50 cm. calculate the pressure at bottom of the breaker.(g=

sweet-ann [11.9K]

Density=1200kg/m^3=p
Height=50cm=0.5m=h
Acceleration due to Gravity=9.8m/s^2=g

$\boxed{\sf Pressure=pgh}$

$\\ \qquad\quad\sf{:}\dashrightarrow Pressure=1200(0.5)(9.8)$

$\\ \qquad\quad\sf{:}\dashrightarrow Pressure=600(9.8)$

$\\ \qquad\quad\sf{:}\dashrightarrow Pressure=5880Pa$

6 0

3 years ago

A loaded 375 kg toboggan is traveling on smooth horizontal snow at 4.50 m/s when it suddenly comes to a rough region. The region

zmey [24]

Answer:

a) The average friction force exerted on the toboggan is 653.125 newtons, b) The rough region reduced the kinetic energy of the toboggan in 92.889 %, c) The speed of the toboggan is reduced in 73.333 %.

Explanation:

a) Given the existence of non-conservative forces (friction between toboggan and ground), the motion must be modelled by means of the Principle of Energy Conservation and the Work-Energy Theorem, since toboggan decrease its speed (associated with due to the action of friction. Changes in gravitational potential energy can be neglected due to the inclination of the ground. Then:

$K_{1} = K_{2} + W_{f}$

Where:

$K_{1}$ , $K_{2}$ are the initial and final translational kinetic energies of the tobbogan, measured in joules.

$W_{f}$ - Dissipated work due to friction, measured in joules.

By applying definitions of translation kinetic energy and work, the expression described above is now expanded and simplified:

$f\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{1}^{2}-v_{2}^{2})$

Where:

$f$ - Friction force, measured in newtons.

$\Delta s$ - Distance travelled by the toboggan in the rough region, measured in meters.

$m$ - Mass of the toboggan, measured in kilograms.

$v_{1}$ , $v_{2}$ - Initial and final speed of the toboggan, measured in meters per second.

The friction force is cleared:

$f = \frac{m\cdot (v_{1}^{2}-v_{2}^{2})}{2\cdot \Delta s}$

If $m = 375\,kg$ , $v_{1} = 4.50\,\frac{m}{s}$ , $v_{2} = 1.20\,\frac{m}{s}$ and $\Delta s = 5.40 \,m$ , then:

$f = \frac{(375\,kg)\cdot \left[\left(4.50\,\frac{m}{s} \right)^{2}-\left(1.20\,\frac{m}{s}\right)^{2}\right]}{2\cdot (5.40\,m)}$

$f = 653.125\,N$

The average friction force exerted on the toboggan is 653.125 newtons.

b) The percentage lost by the kinetic energy of the tobbogan due to friction is given by the following expression, which is expanded and simplified afterwards:

$\% K_{loss} = \frac{K_{1}-K_{2}}{K_{1}}\times 100\,\%$