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Lisa [10]
10 months ago
6

The bending of waves such as sound waves, light waves, and waves in water, around obstacles or the edges of openings is called.

Physics
1 answer:
kolezko [41]10 months ago
4 0

Answer:

Diffraction

Explanation:

Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.

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Assoli18 [71]

Explanation:

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6 0
3 years ago
Read 2 more answers
Suppose your network is connected to another network via a router. Which OSI model layer provides the information necessary to d
RUDIKE [14]

Answer: it is called the "NETWORK LAYER"

Explanation: OSI model means Open System Interconnection model. It have different model layers.

The network layer is the OSI model layer that helps in forwarding packets from network to network, using a network router. It's main function is to connect different network together. It also determine the best virtual circuits(paths) for the data to travel.

Because the question specify that the network is connected to a network router, that means the OSI model layer is network layer.

8 0
3 years ago
A conductor directly connected to the earth is called a ______.
statuscvo [17]

Answer:

ground

Explanation:a conductor connected directly to the earth is called a ground

7 0
3 years ago
What is the difference between reflection and refraction
sineoko [7]

Answer:

Reflection is when light bounces off an object, while refraction is when light bends while passing through an object.

Explanation:

I just learned about this 2 weeks ago actually.

5 0
3 years ago
A straight wire of length 0.56 m carries a conventional current of 0.4 amperes. What is the magnitude of the magnetic field made
djverab [1.8K]

Answer:

The magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.

Explanation:

Given;

length of the straight wire, L = 0.56 m

conventional current, I = 0.4 A

distance of magnetic field from the wire, r = 2.6 cm = 0.026 m

To determine magnitude of magnetic field made by current in the wire, we will apply Bio-Savart Law;

B = \frac{\mu_o}{4\pi r} \frac{LI}{\sqrt{r^2 +(L/2)^2} } \\\\B = \frac{4\pi *10^{-7}}{4\pi *0.026} \frac{0.56*0.4}{\sqrt{(0.026)^2 +(0.56/2)^2} }\\\\B = 3.846*10^{-6}(0.7966)\\\\B = 3.064*10^{-6} \ T

Therefore, the magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.

3 0
3 years ago
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