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adoni [48]
3 years ago
9

A painter is placing a ladder to reach the third story window, which is 23 feet above the ground and makes an angle with the gro

und of 80°. How far out from the building does the base of the ladder need to be positioned? Round your answer to the nearest tenth.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

69

Step-by-step explanation:

You might be interested in
Sam needs a web designer. Designer A is offering her services for an initial $500 in addition to $100 per hour. Designer B is of
gavmur [86]

Answer:

2 hours

Step-by-step explanation:

Let's denote the amount of time we need to find out, t.

=> 600 + 50t < 500 + 100t

or 600 - 500 < 100t - 50t

or 100 < 50t

or 100/50 < t

or t > 2

=> After 2 hours, company B will be cheaper option than company A

3 0
3 years ago
A sample of lake water contains 150grams of salt. If 30% of the water sample is salt, find the number of grams the entire sample
hjlf

Answer:

500 grams

Step-by-step explanation:

Let's say that the total number of grams of the sample is x. We know that 30% of x is salt and we also know this quantity is 150 grams. So, we can write this as:

30% * x = 150

Remember that % is simply "out of 100", so 30% = 30/100 = 0.30. Then:

0.30 * x = 150

Divide both sides by 0.30:

x = 500 grams

Hope this helps!

5 0
3 years ago
The area of the trapezoid is 70 square inches. What is the length of the larger base?
GalinKa [24]

Answer:

20 i think srry if wrong

Step-by-step explanation:

5 0
3 years ago
Analyze the scatterplot below, what prediction can you make about the group of students used in the study from the graph below?
SCORPION-xisa [38]

Answer:

i do not understand

Step-by-step explanation:

8 0
3 years ago
How do you get the same base for the power
zhannawk [14.2K]
64 = 2 ^6
16 = 2^4 = 

2^ 6*(2x+4) = 2^4 * 5x

6(2x+4) = 20x

10/3 x = 2x +4

4/3 x = 4

x = 3

you can also use logarithms like so

(2x+4)ln64 = 5x ln16

ln64/ln16 = 3/2

3/2 * 2x + 3/2 * 4 = 5x

3x + 6 = 5x

2x = 6

x = 3




7 0
3 years ago
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