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3 years ago

Find the equation of the line passing through the points (2 11) and (-8 -19)

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

Answer:

Y=2x+7

Step-by-step explanation:

To find the gradient of the line u have to subtract the y intercepts and the x intercepts

11--9/2--8=20/10=2

Y-11/x-2=2

Y-11=2(x-2)

Y-11=2x-4

Y=2x-4+11

Y=2x+7

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Licemer1 [7]

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alekssr [168]

Answer:

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Step-by-step explanation:

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slamgirl [31]

Answer:

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Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

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Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

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$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

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The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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