Find the equation of the line passing through the points (2 11) and (-8 -19)

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

Answer:

Y=2x+7

Step-by-step explanation:

To find the gradient of the line u have to subtract the y intercepts and the x intercepts

11--9/2--8=20/10=2

Y-11/x-2=2

Y-11=2(x-2)

Y-11=2x-4

Y=2x-4+11

Y=2x+7

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Find the measures of the angles formed by (a) two consecutive radii and (b) a radius and a side of a regular dodecagon.

IgorLugansk [536]

See the picture to better understand the problem

we know that
A regular dodecagon has 12 sides
Central angle of a regular polygon is an angle whose vertex is the center of the polygon with two consecutive radii
thus
the measure of a central angle is
m∠AOC=360/n
where n is the number of sides
so
m∠AOC=360/12-----> 30°

therefore

the answer Part a) is
the measure of the angle formed by two consecutive radii is 30 degrees

Part b)
we know that
OAC is an isosceles triangle
so
OA=OC
m∠OAC=m∠OCA

the sum of the internal angles of a triangle is 180 degrees
so
180=2*m∠OAC+m∠AOC-----> m∠OAC=[180-30]/2----> 75°

the answer part b) is
the measure of the angle formed by a radius and a side is 75°

8 0

3 years ago

If the following two triangles are similar, find X. Show work please

anastassius [24]

The similarity ratio is 20/10 = 2, so x can be found as:

10/2 = x = 5

7 0

3 years ago

Please help me out it would make my day!

nlexa [21]

Answer:

Last option: Square both sides of the equation in step 1 to eliminate the square root.

Step-by-step explanation:

The error is in the process of subtracting 3 from both sides, since +3 is inside the root.

In order to be able to operate with the terms that are inside the root, we need to eliminate the root, and for that we need to square both sides of the equal sign.

6 0

2 years ago

Can anyone help me wit this!!

dybincka [34]

Answer:

See attachment for table values
y₁ = y₂ for x = 6

Step-by-step explanation:

In each case, put the x-value in the formula and do the arithmetic. If you're allowed, you can save some time and effort by realizing that the solution (x) will have to be an even number.

y₁ is an integer value for all integer values of x. y₂ is an integer value for even values of x only. y₁ and y₂ will both be integers (and possibly equal) only when x is even.

For example, for x = 6, we have

... y₁ = 3·6 - 8 = 18 -8 = 10

... y₂ = 0.5·6 +7 = 3 +7 = 10

That is, for x = 6, both columns of the table have the same number (10). That is, y₁ = y₂ for x = 6. The solution to the equation

... y₁ = y₂

... x = 6.