There are 7 numbers between 5 and 11 including 5 and 11. This means there is a one in seven chance of any number. The probability of o 9 is 1/7.
Answer:whats the question
Step-by-step explanation:question?
The expression consists of 4 terms, and each term contains 2 factors.
1) In this expression:
ab +cd + ef +gh
We can make the following definitions:
2) Factors are numbers or letters (in algebra) that we can use to multiply themselves and yields another number.
Terms can be defined as letters, numbers within an expression.
3) Hence, In this expression, we have then:
4 terms: ab, cd, ef, and gh
2 factors per term.
The expression consists of 4 terms, and each term contains 2 factors.
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Answer: Choice C</h3>
Yes they are independent because P(California) = 0.55 approximately and P(California | Brand B) = 0.55 approximately as well
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Explanation:
P(California) is notation that means "probability the person is from California". There are 150 people from California out of 275 total. Therefore, the probability is 150/275 = 0.5454 approximately which rounds to 0.55
Now if I told you "this person prefers brand B", then you would focus your attention solely on the brand B column. The other columns are ignored because you know they don't prefer anything else. With this narrower view, we see that 54 Californians prefer this brand out of 99 total. The probability becomes 54/99 = 0.5454 which rounds to 0.55. We get the same as before.
The notation P(California | Brand B) means "the probability they are from California given they prefer brand B". The vertical line is not the uppercase letter i or lowercase letter L. It is simply a vertical line. In probability notation that vertical line means "given".
We've shown that P(California | Brand B) = 0.55 approximately. The fact that they prefer brand B does not change the original probability. So the two events are independent. If liking brand B did change the probability, then the events would be dependent.
Answer:
The probability that the average mileage of the fleet is greater than 33.8 mpg is 0.695
Step-by-step explanation:
The car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation 3 mpg. We want to find the probability that the average mileage of the fleet is greater than 33.8 mpg, if a pizza delivery company buys 59 of these cars.
We calculate the z-score using:
We substitute 
From the standard normal distribution table, P(X>33.8)=0.695
