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Alina [70]
3 years ago
13

What is the area of a trapezoid if the base is 5, 17, 7 and height is 4

Mathematics
1 answer:
posledela3 years ago
5 0
The area of the trapezoid would be 48
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X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
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Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

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x^2+4x^4-12x^2+9=2

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(4x^2-7)(x^2-1)=0

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4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

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x^2=1

x=\pm1

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y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

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y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

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