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nika2105 [10]
3 years ago
15

Using the defects method, which relationship represents the Law of Cosines if the measure of the included angle between the side

s a and b of ΔABC is less than 90°?
A) area of square c2 = -area of square a2 − area of square b2 + area of defect1 + area of defect2
B) area of square c2 = area of square a2 + area of square b2 + area of defect1 − area of defect2
C) area of square c2 = area of square a2 + area of square b2 − area of defect1 − area of defect2
D) area of square c2 = area of square a2 + area of square b2 + area of defect1 + area of defect2
Mathematics
2 answers:
kramer3 years ago
7 0

Answer:

C !

Step-by-step explanation:

kirza4 [7]3 years ago
4 0
Using the defects method, which relationship represents the Law of Cosines if the measure of the included angle between the sides a and b of ΔABC is less <span>than 90°?

</span><span>C) area of square c2 = area of square a2 + area of square b2 − area of defect1 − area of defect2
</span>
I'm really not familiar with this subject area but I have encountered this problem before and this answer was confirmed. 
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M^1/3 divided by m^1/5
alisha [4.7K]
M^1/3 divided by m^1/5 = m^2/15<span>

m^1/5 divided by m^1/3 = 1/ </span>m^2/15<span>

m^1/3*m^1/5 = m^8/15

(m^1/3)^1/5 = m^1/15

(m^1/3m^1/5)^0 =1</span>
4 0
3 years ago
Kay and Allen sell cell phones. Last month Kay sold 17 more cell phones than Allen. Together they both sold 117 cell phones. How
cricket20 [7]

Answer:

Step-by-step explanation:

K = A + 17

K + A = 117

A + 17 + A  = 117

2A + 17 = 117

2A = 117 - 17

2A = 100

A = 100/2

A = 50 <=== what Allen sold

K + A = 117

K + 50 = 117

K = 117 - 50

K = 67 <==== what Kay sold

8 0
3 years ago
A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at ​​ (−2,
Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.  

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}  

\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{64}=8

Now let us find distance between vertex B and vertex C.

\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{25}=5

Now let us find distance between vertex C and vertex D.

\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{64}=8

Now let us find distance between vertex D and vertex A.

\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}  

\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}    

\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}

\text{Distance between vertex D and vertex A}=\sqrt{25}=5

Now let us add all these distances to find the total distance walked by Jared.  

\text{Total distance walked by Jared}=8+5+8+5

\text{Total distance walked by Jared}=26  

Since we have been given that one unit on the grid equals 1 yard,   therefore, Jared walked a distance equal to 26 yards.  

3 0
3 years ago
PLS HELP ASAP IT DETECT IF ITS Right OR WRONG HELPP
Lilit [14]

Answer:

the answer i believe is right angles

3 0
3 years ago
What is the HCF of two consecutive numbers?
Luba_88 [7]

Answer:  The HCF o two consecutive numbers is always one.

Step-by-step explanation: The reason behind this is that the two consecutive numbers do not have any common factor other than 1. Hence 1 becomes the highest common factor between two consecutive numbers

please mark brainliest

6 0
3 years ago
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