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Over [174]
1 year ago
7

Expressions is equal to 2(40 - p)?

Mathematics
1 answer:
Bumek [7]1 year ago
8 0
80 - 2p
You use the distributive property
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Write the equation of a line, in Point slope form that passes through (5,6) and has a slope of -3​
Mademuasel [1]

Answer:

y = -3x + 21

Step-by-step explanation:

(5,6)

y = mx + b

6 = -3 × 5 + b

solving for b

b = 6 - (-3)(5)

b = 21

Therefore,

y = -3x + 21

7 0
2 years ago
What is the slope and equation of a line parallel to the x-axis passing through point (3,7)
Law Incorporation [45]
Thats when point =0. equation of a line mx +b where m is the slope
and b is the intercept
6 0
2 years ago
In a video game, Agnes scored 20% fewer than Amy. Amy scored 860
vovangra [49]

Answer:

\huge\boxed{\sf Agnes\ Score = 688\ points}

Step-by-step explanation:

\sf = 20 \% \ of \ 860 \\\\= \frac{20}{100} * 860\\\\= 2 * 86\\\\= 172 \ points

Since, Agnes scored 20 % fever than Amy.

So,

Agnes Score = Amy's Points - 20 % of Amy's Points

Agnes Score = 860 - 172

Agnes Score = 688 points

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
8 0
3 years ago
A manufacturer of bolts has a​ quality-control policy that requires it to destroy any bolts that are more than 4 standard deviat
Doss [256]

Answer:

more than 15.40 cm and less than  14.60 cm

Step-by-step explanation:

A manufacturer of bolts has a quality control policy that requires it destroy any bolts that are more than 4 standard deviations from the mean.

mean length= 15 cm

standard deviation= 0.10 cm

4 standard deviation from mean= 15±(4×0.10)

therefore, bolts of length more than 15+0.4, and less than 15-0.4 will be destroyed

= 15.40 cm and 14.60 cm

4 0
3 years ago
Consider the following statement. ∀ integer d, if 6 d is an integer then d = 3. Which of the following is a negation for the sta
omeli [17]

Answer:

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

Step-by-step explanation:

If 6d is an integer, then d = 3

Let's divide the statement into two:

Let "If 6d is an integer" be p and "then d = 3" be q.

The statement is a conditional statement. Therefore, we have

p ⇒ q

The negation of p ⇒q, ¬(p ⇒ q) ≡ p ∧ ¬q

I have attached an image proving the above.

Using this: ¬(p ⇒ q) ≡ p ∧ ¬q

Then, we leave p as it is and negate q.

P is "if 6d is an integer"

q is "then d = 3," hence ¬q is "then d ≠ 3."

Therefore, the negation of "If 6d is an integer, then d = 3" is "If 6d is an integer, then d ≠ 3."

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

6 0
3 years ago
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