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2 years ago

11

20÷2-3×3 use pemdas show your work will mark brainest

2 answers:

nataly862011 [7]2 years ago

7 0

20÷2=10 10-3=7 7×3=21

zvonat [6]2 years ago

4 0

1

Do multiplication/ division before subtraction

When multiplication/ division appear in the calculation together, evaluate from left to right.

20 ÷ 2 - 3 × 3 = 10 - 9 = 1

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Factor each expression 30+10x-40y

Sergio039 [100]

Hello!

To factor you find the biggest number they can be divided by

The biggest number that all the number can be divided by is 10

You put that outside parenthesis

10()

Divide the expression by 10

3 + x - 4y

Put the two together

10(3 + x + 4y)

Hope this helps!

4 0

3 years ago

The inequality 6-2/3

mash [69]

16 over 3 is the answer u write the numerator above the denominator 6 over 1 minus 2 over 3 6 times 3 over 1 x3 minus 2 over 3 u get 18 minus 2 over 3 and subtract 18 and 2 u get 16 over 3

3 0

3 years ago

Read 2 more answers

Find the first four terms of the sequence an = 4n-6

natulia [17]

Answer:

The first four terms of the sequence are-6, -2, 2 and 6

Step-by-step explanation:

The given sequence is $a_n=4n-6$

In order to find the first four term of the sequence we put n =0, 1, 2 and 3.

For n =0

$a_0=4(0)-6=-6$

For n =1

$a_1=4(1)-6=-2$

For n =2

$a_2=4(2)-6=2$

For n =3

$a_3=4(3)-6=6$

Therefore, the first four terms of the sequence are

-6, -2, 2 and 6

5 0

3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago

A wheel has a diameter of 28 inches. What is the approximate distance around the outside of the wheel? Use 3.14 for pi.

prohojiy [21]

Answer:

43.96

Step-by-step explanation:warning might be wrong

8 0

2 years ago