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KiRa [710]
3 years ago
12

You have $59.95 in your wallet and want to buy some new CDs. If the CDs are $11.99 each, what number of CDs, x, can you buy? Wri

te and solve an inequality. Math symbols Relations Geometry Groups Trigonometry Statistics Greek Previous Next
Mathematics
1 answer:
juin [17]3 years ago
3 0

Answer: x≤5

Step-by-step explanation:

Let the one CD be given by= x

So,

11.99x≤ 59.95

or x≤ \frac{59.95}{11.99}

x≤5

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What’s the answer?????!
stepan [7]

Answer:

0.58×0.90=0.522

Step-by-step explanation:

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3 years ago
carlos is baking banana bread.He uses 3/8 cup of brown sugar in one loaf.He is making 6 loaves of banana bread.How much brown su
algol13
Well, if he uses 3/8 cup per loaf and makes 6 loaves  then basically all you will need to do is  3/8 times 6 which =s 24/8. And how many times does 8 go into 24? 3 times, so Carlos will use 3 cups of brown sugar for his banana bread loaves. 


Hope this helps!:);)
4 0
4 years ago
Read 2 more answers
Generic sugar which costs $2.23/kg is made by combining brand X sugar which costs $1.18/kg with brand Y sugar which costs $3.98/
White raven [17]

Answer:

X = 14 kg

Y= 7 kg

Step-by-step explanation:

LET  X and Y equal the amounts of brand X and Y

X = kg of brand X

Y = kg of brand Y

we know:

1)   X    +    Y   =   21    (kg)

2)   1X  +   4Y  =   2(X + Y)        (This is the cost/kg * amounts for total cost)  

Coefficients 1,4,2  are the cost/kg)

substitute eq. 1 (X+Y), = 21 into right side of equation 2

1X + 4Y = (21)*2

use elimination to solve 2 equations

X   +   Y = 21

X   + 4Y = 42        (now subtract,       note:  I wrote the 1X as just X)

------------------

0     -3Y  = -21       OR   Y = 7 kg   so X = (21-7) OR   X = 14 kg

5 0
3 years ago
Help its due rn!!!!!!!!!! Please
Mekhanik [1.2K]

Answer:

= 90 - 23 \\  = 46 \degree

4 0
3 years ago
Sec^6x (secxtanx) - sec^4x (secxtanx) = sec^5x tan^3x
Olegator [25]
Let E the expression of the left side of the equation:

E=\sec^6(x) (\sec (x)\tan (x)) - \sec^4(x) (\sec (x)\tan (x))\\\\
E=\sec^7(x)\tan(x)-\sec^5(x)\tan(x)\\\\
E=\sec^5(x)\tan(x)(\sec^2(x)-1)

We must know that \tan^2(x)+1=\sec^2(x)\iff \sec^2(x)-1=\tan^2(x). So, using in the equation above:

E=\sec^5(x)\tan(x)(\underbrace{\sec^2(x)-1}_{\tan^2(x)})\\\\
E=\sec^5(x)\tan(x)(\tan^2(x))\\\\
\boxed{E=\sec^5(x)\tan^3(x)}

Then, the equation is true.
3 0
4 years ago
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