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2 years ago

Four big water bottles can hold 8 gallons of water. How much water can ten big water bottles hold?

Mathematics

2 answers:

denis-greek [22]2 years ago

6 0

Ten big water bottles can hold 18 gallons of water

professor190 [17]2 years ago

5 0

Ten big water bottles can hold 20 gallons of water.

When writing unit rates, y goes over x. However, in the problem above, x represents the water bottles and y represents the gallons of water.

4/8 (x, y) -> 8/4 (y, x)

8/4 \ 4/4 = 2/1

Now, you know the constant rate of change. There are 2 gallons of water for every 1 big water bottle. Simply multiply 2 by 10.

Since you are looking for how many gallons of water in ten water bottles, multiply 2 gallons of water (I assume you now know that there are 2 gallons of water in every 1 big bottle) by the number of water bottles. In this case, 10.

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2) Brian purchased pens for 75 cents each and pencils for 40 cents each he bought total of 22 writing utensils for $11.95. How m

d1i1m1o1n [39]

Answer:

13 pencils.

Step-by-step explanation:

Let x be the pens and y be the pencils

Given:

Brian purchased pens for 75 cents each and pencils for 40 cents each he bought total of 22 writing utensils for $11.95.

Total pens and pencils is 22

So, $x+y=22$ ----------------(1)

And he bought all utensils for $11.95. and each pen for 75 cents and pencils for 40 cents.

$0.75x+0.40y=11.95$ ------------(2)

solve equation 1 and equation 2 for x and y.

From equation 1.

$x+y=22$

$y=22-x$ ----------------(3)

put y value in equation 2.

$0.75x+0.4(22-x)=11.95$

$0.75x+0.4\times 22-0.4x=11.95$

$0.75x+8.8-0.4x=11.95$

$0.75x-0.4x=11.95-8.8$

$0.35x=3.15$

$x=\frac{3.15}{0.35}$

$x=9$

Now substitute x value in equation 3.

$y=22-9$

$y=13$

So, he buy 13 pencils.

5 0

2 years ago

WILL GIVE BRAINLIEST<br> thank you

crimeas [40]

Answer:

I'm pretty sure the answer is the second choice

Step-by-step explanation:

because you have to add X to both sides

8 0

3 years ago

Robert makes $951 gross income per week and keeps $762 of it after tax withholding. How many allowances has Robert claimed? For

MAXImum [283]

Answer:

Option D,four is correct

Step-by-step explanation:

The tax withholding from the gross income of $951 is the gross income itself minus the income after tax withholding i.e $189 ($951-$762)

The percentage of the withholding =189/951=20% approximately

Going by the multiple choices provided,option with 4,189 dollars seems to the correct option as that is the exact of the tax withholding on Robert's gross income and his earnings fall in between $950 and $960

4 0

2 years ago

Describe and correct the error the student made when writing the equation of the line that passes through (-8,5)

pshichka [43]

Option D (The student should have used as the slope of the perpendicular line.) is correct.

Step-by-step explanation:

We need to identify the error that the student made in finding equation of the line that passes through (-8,5) and is perpendicular to y = 4x + 2

The slope of the required line would me -1/m because both lines are perpendicular.

So, slope of new line will be: -1/4

because the equation of slope-intercept form is: $y=mx+b$ where m is the slope

Now, for finding equation the student used point slope form i.e $y-y_1=m(x-x_1)$

where y_1 and x_1 are the points and m is the slope.

Putting values:

x_1=-8, y_1=5 and m=-1/4

$y-5=-\frac{1}{4}(x-(-8))\\y-5=-\frac{1}{4}(x+8)\\y-5=-\frac{1x}{4}-2\\y=-\frac{1x}{4}-2+5\\y=-\frac{1x}{4}+3$

This is the correct solution.

The student made error by using the wrong slope he used 2 instead of -1/4

in the step $y-5 = 2(x-(-8))$

So, Option D (The student should have used as the slope of the perpendicular line.) is correct.

Keywords: Equation of line using Slope

Learn more about Equation of line using Slope at:

#learnwithBrainly

3 0

2 years ago

Read 2 more answers

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form? 5x + 3y = 18 5x – 3y = 30

ddd [48]

$\bf C(\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})\qquad 
D(\stackrel{x_2}{6}~,~\stackrel{y_2}{0})
\\\\\\
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-5)}{6-3}\implies \cfrac{0+5}{6-3}\implies \cfrac{5}{3}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{5}{3}(x-3)\implies y+5=\cfrac{5}{3}(x-3)$

$\bf \stackrel{\textit{multiplying both sides by LCD of 3}}{3(y+5)=3\left[ \cfrac{5}{3}(x-3) \right]}\implies 3y+15=5(x-3)
\\\\\\
3y+15=5x-15\implies -5x+3y=-30\implies \stackrel{\textit{multiplying by -1}}{5x-3y=30}$

bearing in mind the standard form uses all integers, and the x-variable cannot have a negative coefficient.

6 0

3 years ago

Read 2 more answers