re are 5 short rows of chairs, each with an equal number of chairs. On a crowded day, the ushers added 2 chairs to each long row
1 answer:
You might be interested in
10/8 in simplest form:
First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.
Factors of 10: 1, 2, 5, 10
Factors of 8: 1, 2, 4, 8
We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.
Second, divide the numerator and the denominator by the GCF (2).
Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get:
Answer in fraction form:
Answer in decimal form:
Answer in mixed number form:
First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.
Factors of 10: 1, 2, 5, 10
Factors of 8: 1, 2, 4, 8
We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.
Second, divide the numerator and the denominator by the GCF (2).
Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get:
Answer in fraction form:
Answer in decimal form:
Answer in mixed number form:
Answer:
(3, 0).
Step-by-step explanation:
dentifying the vertices of the feasible region. Graphing is often a good way to do it, or you can solve the equations pairwise to identify the x- and y-values that are at the limits of the region.
In the attached graph, the solution spaces of the last two constraints are shown in red and blue, and their overlap is shown in purple. Hence the vertices of the feasible region are the vertices of the purple area: (0, 0), (0, 1), (1.5, 1.5), and (3, 0).
The signs of the variables in the contraint function (+ for x, - for y) tell you that to maximize C, you want to make y as small as possible, while making x as large as possible at the same time.
Hence, The Answer is ( 3, 0)
Hi there! The answer is 30.
We need to use PEMDAS to simplify.
P = parenthesis
E = Exponents
M = Multiply
D = Dividing
A = Adding
S = Subtracting
First find the exponents inside the middlest parenthesis.
Now add inside the parenthesis.
Multiply inside the parenthesis that are left.
Divide inside the parenthesis
Add inside the parenthesis.
Multiply.
~ Hope this helps you!
We need to use PEMDAS to simplify.
P = parenthesis
E = Exponents
M = Multiply
D = Dividing
A = Adding
S = Subtracting
First find the exponents inside the middlest parenthesis.
Now add inside the parenthesis.
Multiply inside the parenthesis that are left.
Divide inside the parenthesis
Add inside the parenthesis.
Multiply.
~ Hope this helps you!