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olga2289 [7]
4 years ago
11

Suppose that two cards are randomly selected from a standard 52-card deck. (a) What is the probability that the first card is a

spadespade and the second card is a spadespade if the sampling is done without replacement? (b) What is the probability that the first card is a spadespade and the second card is a spadespade if the sampling is done with replacement?
Mathematics
1 answer:
Roman55 [17]4 years ago
6 0

Answer:

a.\frac{1}{17}

b.\frac{1}{16}

Step-by-step explanation:

We are given that two cards are drawn are randomly selected from a standard 52- cards deck.

Total cards=52

Total number of spade cards=13

Probability=\frac{number\;of\;favourable\;cases}{total\;number\;of cases}

a.The probability of drawing two cards first card is spade and second card is spade without replacement =\frac{13}{52}\times \frac{12}{51}

The probability of drawing two cards first card is spade and second card is spade=\frac{1}{17}

b. The probability of drawing two cards first is spade and second card is a spade with replacement =\frac{13}{52}\times\frac{13}{52}

The probability of drawing two cards first is spade and second card is a spade with replacement =\frac{1}{16}

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adelina 88 [10]

Answer:

6

Step-by-step explanation:

The maximum value of the sin function is at \dfrac{\pi}{2}, when sin is equal to 1. Since you need to multiply pi/12 by 6 to get to pi/2, the maximum amount of people will be at the square after 6 hours. Hope this helps!

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Evaluate 4a-3b when a=5 and b=-2
den301095 [7]
4a - 3b

4(5) - 3(- 2)
20 + 6
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26 is your answer. 
6 0
3 years ago
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I will give brainliest to correct answer
FromTheMoon [43]

Answer:

D

Step-by-step explanation:

If the polynomial p(x) is divided by a polynomial of the form x+k (which accounts for all of the possible answer choices in this question), the result can be written as

p(x)/x+k = q(x) + r/x+k

where q(x) is a polynomial and r is the remainder. Since x+k is a degree-1 polynomial (meaning it only includes x^{1} and no higher exponents), the remainder is a real number.

Therefore, p(x) can be rewritten as p(x) = (x+k)q(x) + r, where r is a real number.

The question states that p(3) = −2, so it must be true that

−2 = p(3) = (3+k)q(3) + r

Now we can plug in all the possible answers. If the answer is A, B, or C, r will be 0, while if the answer is D, r will be −2.

A. −2=p(3)=(3+(−5))q(3)+0

−2=(3−5)q(3)

−2=(−2)q(3)

This could be true, but only if q(3)=1

B. −2=p(3)=(3+(−2))q(3)+0

−2=(3−2)q(3)

−2=(−1)q(3)

This could be true, but only if q(3)=2

C. −2=p(3)=(3+2)q(3)+0

−2=(5)q(3)

This could be true, but only if q(3) = −2/5

D. −2=p(3)=(3+(−3))q(3)+(−2)

−2=(3−3)q(3)+(−2)

−2=(0)q(3)+(−2)

This will always be true no matter what q(3) is.

Of the answer choices, the only one that must be true about p(x) is D, that the remainder when p(x) is divided by x−3 is -2.

The final answer is D.

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zubka84 [21]

Answer:

32

Step-by-step explanation:

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3 years ago
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