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Bond [772]
2 years ago
8

In their 1943 meeting at Casablanca, Allied leaders decided to invade

Mathematics
1 answer:
N76 [4]2 years ago
6 0
In their 1943 meeting at Casablanca, Allied leaders decided to invade Italy.
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Answer:1.55?

Step-by-step explanation:

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3x-2&gt;4<br> What’s the answer
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2

Step-by-step explanation:

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Do<br>main of ln(2x+3/×-1)
lozanna [386]
<span>so your equation  would be  2x-3=-1  then your answer would be -1

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3 years ago
Use The four step process to find the slope of the tangent line to the graph of the given function at any point. ( simplify your
hodyreva [135]

Answer:

The answer to your question is: 16x + 3

Step-by-step explanation:

Step 1 :      f(x) = 8x² + 3x

                f(x +h) =  8(x + h)² + 3( x + h)

                f(x + h) = 8( x² + 2xh + h²) + 3( x + h)

                f (x + h) = 8x² + 16xh + 8h² + 3x + 3h

Step 2 f(x+h) - f(x) =  8x² + 16xh + 8h² + 3x + 3h - ( 8x² + 3x)

                              = 8x² + 16xh + 8h² + 3x + 3h - 8x² -3x

                              = 16xh + 8h² + 3 h

Step 3 f(x + h) - f(x)/ h = h(16x + 8h + 3) /h

                                    = 16x + 8h + 3

Step 4 lim  f(x + h) - f(x)/ h = lim 16x + 8h + 3  = lim 16x + 8(0) + 3 = 16x + 3

        h ⇒0                           h ⇒0                     h ⇒0

3 0
3 years ago
A population is known to be normally distributed with a standard deviation of 2.8. (a) Compute the 95% confidence interval on th
Ugo [173]

Answer:

Step-by-step explanation:

Mean = sum of terms/number of terms

The mean of the given sample is

(8 + 9 + 10 + 13 + 14 + 16 + 17 + 20 + 21)/9 = 14.2

a)

For a confidence level of 95%, the corresponding z value is 1.96.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 1.96 × 2.8/√9

= 14.2 ± 1.96 × 0.933

= 14.2 ± 1.83

The lower end of the confidence interval is 12.37

The upper end of the confidence interval is 16.03

b)

For a confidence level of 99%, the corresponding z value is 2.58

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 2.58 × 2.8/√9

= 14.2 ± 2.58 × 0.933

= 14.2 ± 2.4

The lower end of the confidence interval is 11.8

The upper end of the confidence interval is 16.6

3 0
2 years ago
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