5x^2y/15xy simplified?
1 answer:
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Recall your d = rt, distance = rate * time
thus
notice, the first car leaves at "x" time, the other leaves on hour later, or x + 1
the first car travels some distance "d", whatever that is, thus
the second car, picks up the slack, or the difference, they're 380 miles
apart, thus the difference is 380-d
thus
notice, the first car leaves at "x" time, the other leaves on hour later, or x + 1
the first car travels some distance "d", whatever that is, thus
the second car, picks up the slack, or the difference, they're 380 miles
apart, thus the difference is 380-d