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svp [43]
3 years ago
9

a recipe for cookies calls for 10 1/6 cups of sugar. krystal has already put in 4 2/3 cups. how many more cups does she need to

put in
Mathematics
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

5 1/2 cups

Step-by-step explanation:

10 1/6 = \frac{61}{6} cups

10 x 6 + 1

\frac{61}{6}

4 2/3 = \frac{14}{3} cups

4 x 3 + 2

\frac{14}{3}

Find a common denominator (6)

\frac{14}{3} = \frac{28}{6}

\frac{14}{3} · 2 = \frac{28}{6}

\frac{61}{6} - \frac{28}{6} = \frac{33}{6}

\frac{33}{6} or 5 1/2 cups

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6
Ede4ka [16]

Answer:

5 percent per annum

Step-by-step explanation:

interest rate:

interest: $1800

principal: $18000

duration: 2 years

1800/ 18000 * 100

result is 10%

Since interest is 10% in 2 years, 10% / 2

interest is 5% per year.

8 0
2 years ago
This is part 1. Please help
ahrayia [7]
For the first one you would do:
X rad 3=7 divide by rad 3 in both sides and you don’t wanna leave a radical in the denominator so multiply rad 3 in both denom. And numerator and then you get 7rad3/3.

A 30:60:90 triangle always have n:2n:n rad 3 so since 2n=10 you would get n=5 and since BC is n rad3 so you would get 5rad 3.

In a 45:45:90 triangle it is n:n:n rad 2, since AC=3 then AB= 3 and then BC= 3 rad 2

Since AC and AB are congruent you they both would be 12 so it is true.

6 0
3 years ago
A bicycle lock has a four-digit code. The possible digits, 0 What is the probability that the lock code will begin with
nika2105 [10]

Answer:

0.1-0.6

Step-by-step explanation:

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities

the second digit is any of the remaining 9, after having picked one. 

and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=

b. What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6

8 0
2 years ago
Read 2 more answers
Helpppp pleaseeee!!!!
dimaraw [331]
I could be wrong but I think you solve for y then graph it then find where the lines intersect. You’re using ed puzzle though so just rewatch the part of the video and you’ll get the answer.
6 0
3 years ago
Read 2 more answers
The equation of the line through point (-4,0) and parallel to the y-axis is
seraphim [82]

Answer:y=-4

Step-by-step explanation:

3 0
3 years ago
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