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Maslowich
3 years ago
13

Answer needed ASAP, first correct answer gets brainliest!

Mathematics
1 answer:
Simora [160]3 years ago
5 0

Answer:

Ok. I got 15.

Step-by-step explanation:

Tbh, I just did a whole bunch of guessing with random prime numbers but here is the work for the answer:

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-2 (x + 4) – (3x – 8)<br> What it equals
Alja [10]

Answer:

-2x+-8-3x-8

Step-by-step explanation:

-2 times x =-2x  

-2 times 4=-8

8 0
3 years ago
Read 2 more answers
What is the exact volume of the cylinder 12 in and 20 in
rusak2 [61]
Which one is the radius and which one is the height?
6 0
4 years ago
the ratio of the length to width in a full-size cello is approximately 8 to 3. What is the width of a full-size cello that is 45
Brut [27]

Answer:

w = 16.875 inches

Step-by-step explanation:

Given that the ratio of the length to width in a full-size cello is approximately 8 to 3.

This will be a constant for all cellos

Using the above we can find out length if we know width and vice versa.

Here we know the length = 45 inches

Since \frac{l}{w} =\frac{8}{3} =\frac{45}{w}

BY cross multiplication we find that

8w = 3(45)

Or w = 16.875 inches

Verify:

Let us check our answer by comparing with proportion

l/w = 45/16.875 = 8/3

Hence our answer is right

6 0
3 years ago
Read 2 more answers
The radius of the circle x^2+y^2 +px+6y-3=0 is 4. find the possible values of p​
worty [1.4K]

Here, the given equation is,

x^2+y^2+px+6y-3=0

By copairing it with x^2+y^2+2gx+2fy+c=0, we get,

2g=p or, g=p/2

2f=6 or, f=3

c=-3

now the radius is,

r^2=g^2+f^2-c

or, 4^2=(p/2)^2 +3^2 -(-3)

or, 16= p^2/4 +9+3

or, 16-9-3=p^2/4

or p^2/4=4

or, p^2=4×4

or p^2=4^2

or p=4

therefore the rewuired value of p is 4.

6 0
3 years ago
Read 2 more answers
I only need the answer
irina [24]

Answer:

1

Step-by-step explanation:

The given equation of the function is y = -a·(x - h)² + 1

The positive constants of the equation = <em>a</em>, and <em>h</em>

The points the function crosses the x-axis = 2, and 4

Where the function crosses the x-axis, y = 0, and x = 2, and 4, therefore, when x = 2, we have;

y = 0 = -a·(2 - h)² + 1

When x = 4, we have;

0 = -a·(4 - h)² + 1

-a·(2 - h)² + 1 = -a·(4 - h)² + 1

-a·(2 - h)² = -a·(4 - h)²

(2 - h)² = (4 - h)²

±(2 - h) = +#±(4 - h)

When

(2 - h) is negative, and (4 - h) is positive, but the same magnitude, we have';

-(2 - h) = +(4 - h)

2·h = 4 + 2 = 6

h = 3

0 = -a·(4 - h)² + 1 = -a·(4 - 3)² + 1 = -a + 1

Therefore, a = 1

5 0
3 years ago
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