Find the Missing Numerator and Denominator

Mathematics

1 answer:

n200080 [17]2 years ago

7 0

Answer:

missing denominator: 5

missing numerator: 3

Step-by-step explanation:

You know the product of fractions is formed by multiplying numerators and multiplying denominators.

$\dfrac{3}{d}\times\dfrac{n}{4}=\dfrac{3n}{4d}=\dfrac{9}{20}$

This gives rise to two equations:

3n = 9 ⇒ n = 3

4d = 20 ⇒ d = 5

The missing denominator is 5; the missing numerator is 3.

$\dfrac{3}{5}\times\dfrac{3}{4}=\dfrac{9}{20}$

You might be interested in

A train leaves at 12.13 and arrives at its destination at 13.03. If the train travelled 83 km, what was it's average speed in km

Mama L [17]

Answer:

1.7km/h

Step-by-step explanation:

speed is distance over time,the time difference is 50 min and the distance is 83,you divide 83 by 50 to give you the answer

3 0

3 years ago

The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func

alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

$h(t)=-16t^2 + 96t$

Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

$To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq 0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq 0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)$

$Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq 0\\-112 \geq 0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq 0\\80 \geq 0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq 0\\-112 \geq 0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution$