angle ABE is equivalent
to the whole angle, and it measures 2b. <span>
while the angle ABF is only a portion of angle ABE, and it
measure 7b - 24.
<span>since we know the measure of the whole angle and a part of
the angle, we can then subtract to find the left over angle (angle EBF), so
Angle EBF = Angle ABE - Angle ABF </span></span>
Angle EBF = 2b – (7b –
24)
<span>Angle EBF = 24 – 5b</span>
No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.
Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have
and since the relation of order "<" is transitive, this implies
Answer:
47/10 = 4 7/10
Step-by-step explanation:
3 2/5 + 1 3/10
1. Write mixed numbers as improper fractions:
17/5 + 13/10
2. Write equivalent fractions with a common denominator:
34/10 + 13/10
3. Add the numerators over the common denominator.
47/10
4. Simplify.
4 7/10
Answer: sin u = -5/13 and cos v = -15/17
Step-by-step explanation:
The nice thing about trig, a little information goes a long way. That’s because there is a lot of geometry and structure in the subject. If I have sin u = opp/hyp, then I know opp is the opposite side from u, and the hypotenuse is hyp, and the adjacent side must fit the Pythagorean equation opp^2 + adj^2 = hyp^2.
So for u: (-5)^2 + adj^2 = 13^2, so with what you gave us (Quad 3),
==> adj of u = -12 therefore cos u = -12/13
Same argument for v: adj = -15,
opp^2 + (-15)^2 = 17^2 ==> opp = -8 therefore sin v = -8/17
The cosine rule for cos (u + v) = (cos u)(cos v) - (sin u)(sin v) and now we substitute: cos (u + v) = (-12/13)(-15/17) - (-5/13)(-8/17)
I am too lazy to do the remaining arithmetic, but I think we have created a way to approach all of the similar problems.
