Answer:
1. The parents genotypes could have been BO and AO
2. wire-hair
Explanation:
There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:
Blood type possible genotypes
Type A AA, AO
Type B BB, BO
Type AB AB
Type O OO
Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO for them to be able to produce a child with OO. a cross between these two could give rise to OO.
Question 2
Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).
thus, in a cross between homozygous wire haired and smooth haired, we will have:
homozygous wire haired homozygous smooth haired
P gen SS x ss
F1 gen. Ss
phenotype: wire haired
<span>The key points about cell theory are as follows:
1. All living organisms are made up of cells; the organisms may be unicellular or multi cellular.
2. The cell is the basic unit of life.
3. New cells are derived from pre-existing cells.
4. All cells maintain homeostasis.
Some new facts have been added to these basic facts; the new facts added include the following:
(A). Energy flow occur withing all living cells.
(B). Hereditary information derived from DNA is passed from cell to cell.
(C). All living cells are made up of the same basic chemical compositions.</span>
Answer:
Water would not be able to form hydrogen bonds.
Explanation:
I'd say A: tidal waves. B, C, and D don't really seem to fit for me.
