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12345 [234]
3 years ago
15

Which equation is represented by the graph y={x} + 1 y={x+1] y={x]-1 y={x-1]

Mathematics
1 answer:
OverLord2011 [107]3 years ago
6 0
The third one is correct
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Use the substitution method to solve the system of equations. y=4x 8x+y=18
RUDIKE [14]

Answer:

x=3/2, y=6

Step-by-step explanation:

plz mark brainliest!

4 0
3 years ago
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General douglas MacArthur, one of the leading generals in World War II was born in 1880 and died in 1964 how old was he when he
malfutka [58]

Answer: he was 84 years old when he died and the fractional part of a century that he live is 21/25

Step-by-step explanation:

General Douglas MacArthur, one of the leading generals in World War II was born in 1880. He died in 1964. The number of years that he lived would be the year he died - the yea he was born. Therefore,

His age when he died

= 1964 - 1880 = 84 years.

The number of years in a century is 100. Therefore, the fractional part of a century that he lived would be

84/100 = 21/25

4 0
4 years ago
during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak
STatiana [176]
<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

f(t)=-16t^{2}+64t+4

Where,

a=-16\\b=64\\c=4

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0

Using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0
4 years ago
A recipe for cookies called for 2/3 of a cup of sugar per batch.Elena used 5 1/3 cups of sugar to make multiple batches of cooki
Nookie1986 [14]

Answer: 8 batches

explanation: 5 1/3 divided by 2/3 equals 8. To find out how many batches were made, you need to divide the total amount used by the amount needed for one batch.

5 0
3 years ago
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1. A dilation with a scale factor of 4 and centered at the origin is applied to AB¯¯¯¯¯ with endpoints A(1, 3) and B(5, 3). Drag
mafiozo [28]
1. (-4,-1) 2.A' (4,12) B'(20,12) 3.B' 4.2  5. 1/8 hope u got them all right  :p 
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3 years ago
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