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3 years ago

6 2/3 * -4 1/5 i really need help

Mathematics

1 answer:

deff fn [24]3 years ago

3 0

Answer:

-28

Step-by-step explanation:

6 2/3*-4 1/5=

20/3*-21/5=

4/3*-21/1=

4/1*-7/1=

-28

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D. Calculate the volume of Laurel's new box. Show your thinking clearly.

bezimeni [28]

The correct answer is 336 cubic inches.
6•8•5=240
9-5=4
4•6/2=12
12•8=96
240+96=336

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2 years ago

Alex deposited x dollars into a new account that earned 8 percent annual interest, compounded annually. One year later Alex depo

djverab [1.8K]

Answer:

Step-by-step explanation:

Start by writing out w in terms of x. After one year, there is 1.08*x dollars in the account. x dollars are then deposited, giving us a total of 1.08*x + x (normally we would simplify this to 2.08 but looking at the answers this is not a good idea.) Next, multiply by 1.08 to account for the 2nd year's interest. This brings to total to w = 1.08(1.08*x + x) = (1.08^2)*x + 1.08*x. Factoring out x, we are left with w = (1.08^2 + 1.08) * x. Dividing both sides by (1.08^2 + 1.08), we are left with x = w/(1.08^2 + 1.08) so the answer is d.

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3 years ago

I need help with slopes in math

e-lub [12.9K]

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2 years ago

Read 2 more answers

Which properties were used to prove that the expressions 7 x + 4 minus x minus 2 and 6 x + 2 are equivalent?

maxonik [38]

I believe is A and D or something

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3 years ago

An English teacher needs to pick 9 books to put on his reading list for the next school year, and he needs to plan the order in

Nikitich [7]

Answer: $4.37\times10^3$

Step-by-step explanation:

Given : Number of choices for novels = 4

Number of choices for plays = 6

Number of choices for poetry books = 5

Number of choices for nonfiction books = 5

Total books =4+6+5+5=20

If he wants to include all 4 novels, then the number of books left to select = 9-4=5

Remaining choices for books = 20-4=16

Number of combinations of n things taking r at a time : $\dfrac{n!}{r!(n-r)!}$

Then, the number of different reading schedules are possible :_

$^4C_4\times^{16}C_5\\\\=\dfrac{4!}{4!(4-4)!}\times\dfrac{16!}{5!(16-5)!}\\\\=(1)\times\dfrac{16\times15\times14\times13\times12\times11!}{120\times11!}\\\\=4368=4.368\times10^3\approx4.37\times10^3$

Hence, the required answer is $4.37\times10^3$ .

8 0

2 years ago