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ValentinkaMS [17]
3 years ago
9

What are the real and complex solutions of the polynomial equation? x^3-64=0

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

Step-by-step explanation:

A difference of two perfect cubes,  x^3 - y^3 can be factored into

(x-y) • (x^2 +xy +y^2) =0  equation 1

x ^3 - 64 = 0

(x)^3 - (4)^3 = 0   equation 2

Now substituting equation 2 into equation 1, we get

(x-4) (x^2+(x).(4) +(4)^2) = 0

(x-4) (x^2+4x+16) = 0

so the solutions are

1) x - 4 =0

x=4

x^2 + 4x + 16 = 0

By using the quadratic formula we get the followig solutions:

          - B  ±  √ B2-4AC

 x =   ————————

                     2A

x =(-4-√-48)/2=-2-2i√ 3 = -2.0000-3.4641i

x =(-4+√-48)/2=-2+2i√ 3 = -2.0000+3.4641i

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3 years ago
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Answer:

See explanation

Step-by-step explanation:

Solution:-

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- Similarly, the volume of cone ( V_c ) is represented by:

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Where,

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- We will represent a proportionality of Volume ( V ) with respect to ( r ):

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Where,

            C: The constant of proportionality

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- Hence, the relations for each of the two bodies becomes:

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                                          &

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