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2 years ago

PLEASE HELP (ASAP)

Mathematics

2 answers:

Alex_Xolod [135]2 years ago

4 0

Answer:

x = 50

Step-by-step explanation:

Angle <BPR and angle <PRD are supplementary angles so their sum is equal to 180

m<BPR + 115 = 180 subtract 115 from both sides

m<BPR = 65

angles:

<APQ, x, and <BPR form a straight line and so their sum is equal to 180

65 + x + 65 = 180 add like terms

130 + x = 180 subtract 130 from both sides

x = 50

Alja [10]2 years ago

3 0

Angle x of the triangle PQR is 53 degrees.

Angle x is gotten by alternate angle relationship.

<h3>How to find an angle in a triangle?</h3>

Line AB is parallel to line CD

Therefore,

AB║CD

Hence,

62 + x = 115(alternate angles)

62 - 62 + x = 115 - 62

x = 53°

We got the angle x degrees from alternate angle relationship.

learn more on angles here: brainly.com/question/13912082

#SPJ1

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Please help Which of the following inequalities is graphed on the coordinate plane?

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Answer:

The inequality which represents the graph is y ≤ -2x + 1 ⇒ A

Step-by-step explanation:

To solve the question you must know some facts about inequalities

If the sign of inequality is ≥ or ≤, then it represents graphically by a solid line

If the sign of inequality is > or <, then it represents graphically by a dashed line

If the sign of inequality is > or ≥, then the area of the solutions should be over the line

If the sign of inequality is < or ≤, then the area of the solutions should be below the line

Let us study the graph and find the correct answer

∵ The line represented the inequality is solid

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3 years ago

Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point A(-2,3), we get;

$(-2,3)\rightarrow (-2,-3)$

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point B(0,3), we get;

$(0,3)\rightarrow (0,-3)$

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point C(-1,-1), we get;

$(-1,-1)\rightarrow (-1,1)$

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

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