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3 years ago

Identify the monomial function(s) that have a maximum.

Mathematics

2 answers:

Irina-Kira [14]3 years ago

7 0

y=-3x^4

y=-2x^12

3 and 4 are the correct options

natima [27]3 years ago

4 0

Answer:

Step-by-step explanation:

For a function f to have a maximum as per derivative rule we have to have

f'(x) =0, f"(x) <0

If second derivative =0 also then it is not maximum but point of inflections

Whenever f(x) = ax^n

we have

f'(x) = 0 gives x=0 and

f"(x) = n(n-1) ax ^(n-2)

So for n greater than or equal to there cannot be any maximum

And also for a straight line

y =-4x

y'=-4 and y"-0

No maximum

So only maximum can be for a funciton of the form y = ax^2

Here we do not have that all degrees are either 1 or greater than 1.

So no maximum for any funciton.

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Please help *THIS IS ON PERSONAL FINANCIAL LITERACY "

Crank

Answer:

I think the answer is $56,600

Step-by-step explanation:

I'm pretty sure you're just going to add $63,000+$8,400+$2,900+$1,1000. Then when you get a total of $75,400 and then I think you are going to subtract $15,400 from $75,400, you should get $60,000 then subtract $3,400 and you get $56,600.

7 0

3 years ago

Multiply (2x^2-3x+5)(x^2+4x+1)

DochEvi [55]

Answer:

$2x^2-12x+5$

Step-by-step explanation:

$(2x^2-3x+5)(x^2+4x+1)\\(2x^2-12x+5)$

3 0

3 years ago

Which statement is true?

love history [14]

<h2>Hello!</h2>

The answer is:

The second option,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}$

<h2>Second option,</h2>

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

The statement is true, we can prove it by using the following properties of exponents:

$(a^{b})^{c}=a^{bc}$

$\sqrt[n]{x^{m} }=x^{\frac{m}{n} }$

We are given the expression:

$(\sqrt[m]{x^{a} } )^{b}$

So, applying the properties, we have:

$(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }$

Hence,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Third option,</h2>

$a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}$

<h2>Fourth option,</h2>

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }$

Hence, the answer is, the statement that is true is the second statement:

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Have a nice day!

6 0

3 years ago

Using the frequency table below

Andrews [41]

Answer:

50%

Step-by-step explanation:

if you look below girls (in total) bought 100 pepsi colas and thats half of the total (200)

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3 years ago

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mojhsa [17]

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3 years ago