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3 years ago

Identify the monomial function(s) that have a maximum.

Mathematics

2 answers:

Irina-Kira [14]3 years ago

7 0

y=-3x^4

y=-2x^12

3 and 4 are the correct options

natima [27]3 years ago

4 0

Answer:

Step-by-step explanation:

For a function f to have a maximum as per derivative rule we have to have

f'(x) =0, f"(x) <0

If second derivative =0 also then it is not maximum but point of inflections

Whenever f(x) = ax^n

we have

f'(x) = 0 gives x=0 and

f"(x) = n(n-1) ax ^(n-2)

So for n greater than or equal to there cannot be any maximum

And also for a straight line

y =-4x

y'=-4 and y"-0

No maximum

So only maximum can be for a funciton of the form y = ax^2

Here we do not have that all degrees are either 1 or greater than 1.

So no maximum for any funciton.

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Use Newton's method with initial approximation x1 = 1 to find x2, the second approximation to the root of the equation x4 − x −

drek231 [11]

Answer:

$x_{2} = 0.0000$

Step-by-step explanation:

The formula for the Newton's method is:

$x_{i+1} = x_{i} + \frac{f(x_{i})}{f'(x_{i})}$

Where $f' (x_{i})$ is the first derivative of the function evaluated in $x_{i}$ .

$x_{i+1} = x_{i} + \frac{x_{i}^{4}-x_{i}-3}{4\cdot x_{i}^{3}-1}$

Lastly, the value of $x_{2}$ is determined by replacing $x_{1}$ with its numerical value:

$x_{2} = x_{1} + \frac{x_{1}^{4}-x_{1}-3}{4\cdot x_{1}^{3}-1}$

$x_{2} = 1.0000 + \frac{1.0000^{4}-1.0000-3}{4\cdot (1.0000)^{3}-1}$

$x_{2} = 0.0000$

8 0

2 years ago

Find the perimeter of a regular octagon whose side is "a" units

Zinaida [17]

Answer:

I think its 8a because in a regular octagon we have 8 sides.

4 0

2 years ago

If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm

natulia [17]

Answer:

Step-by-step explanation:

This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

$F= ke$

where F is the applied force in N

k is the spring constant N/m

e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= $\frac{15}{100}$ = $0.15m$

we can solve for the spring constant k

we also know that the force F = mg

assuming $g=9.81m/s^{2}$

therefore

$24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\$

We can use this value of k to solve for the mass that will cause an extension of $10cm= 0.1m$

$x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg$

5 0

3 years ago

Anyone know the answer?

SIZIF [17.4K]

Answer:

Step-by-step explanation:

No function, because the same output can't have two different inputs.

7 0

3 years ago

Answer? please help :))

gtnhenbr [62]

Answer:

(0,1)(4,9)

Step-by-step explanation:

8 0

3 years ago