7. Find the exact value of a) cos (195) b) csc (75) Make sure to show each step

What is the value of the function when x = 1?

creativ13 [48]

On the graph, we can see that when x=1, y=0.

But we don't even need to bother opening the attachment
and studying the graph !

In your question, you said that one point on the function is (1, 0) .
That means that when 'x' is 1, 'y' is zero. And there you are !

6 0

3 years ago

64.3- 3 x 23 - 2 is what.

Lena [83]

Answer: -6.7

Step-by-step explanation:

64.3−(3)(23)−2

=−6.7

3 0

3 years ago

Read 2 more answers

True or False, In Euclidean geometry, there is only one equilateral triangle

docker41 [41]

True, In Euclidean geometry an equilateral triangle must be a 60-60-60 triangle.

Hope This Helps!!!

5 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

How to factor 6x^2-48x-120

mamaluj [8]

Hello there!

Simply find a common term that they all have!

So they can all be divided by 6, right? So let's take a 6 out.

6 (x^2-8x-20)

Now factor the terms in the parenthesis!

6 (x-10) (x-2)

^ This is NOT your answer!!

Tip: When looking at (x^2-8x-20), look at the middle term. (-8x). Since it's negative, either (x-10) or (x-2) can be negative.

Which one is negative? Well, is the 8 positive or negative? Since the 8 is negative, the parenthesis bigger number (x-10) will be negative!

So it'll be:

6 (x-10) (x+2)

ALWAYS double check your answer by foiling! :)

Hope this helped!

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6 0

3 years ago