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Kruka [31]
3 years ago
7

What is 2.8 × 104 in standard form?

Mathematics
2 answers:
masya89 [10]3 years ago
5 0

Answer:

291.2

Step-by-step explanation:

VMariaS [17]3 years ago
3 0

Answer:

28000

Step-by-step explanation:

<h2><u>Standard form </u></h2>

2.8 * 10^4

in standard form means

2.8 * ( 10 * 10 * 10 * 10 )

this is because  10 ^4 is interpreted as  ( 10 * 10 * 10 * 10 )

hence 2.8 * 10^4

=<u> 28000</u>

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From 1-10, if a number is picked at random, what is the probability of obtaining an odd number?
SCORPION-xisa [38]
The probability of obtaining an odd number is 1/2 or 50%.
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3 years ago
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A 5 in x 7 in picture is in a frame of uniform width x. The area of the picture and the frame together is 99 in2. How wide is th
algol13

Answer: B. 2 inch

Step-by-step explanation:

Let x represent the uniform width of the frame.

The original dimensions of the picture is 5 in x 7 in. This means that the new width of the picture together with the frame is (5 + 2x) in and the new length of the picture together with the frame is (7 + 2x) in.

The formula for determining the area of a rectangle is expressed as

Area = length × width

The area of the picture and the frame together is 99 in2. Therefore,

(5 + 2x)(7 + 2x) = 99

35 + 10x + 14x + 4x² = 99

4x² + 24x + 35 - 99 = 0

4x² + 24x - 64 = 0

Dividing through by 4, it becomes

x² + 6x - 16 = 0

x² + 8x - 2x - 16 = 0

x(x + 8) - 2(x + 8) = 0

x - 2 = 0 or x + 8 = 0

x = 2 or x = - 8

The width cannot be negative. So

x = 2 in

5 0
3 years ago
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Five squared (4+6 divided by 2
RoseWind [281]
5^2(4+6)/2

25(10)/2

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3 years ago
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What’s the inverse function for f(x) 6x-5
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Answer:

g(x)= (1/6)x+5/6 is the inverse function of f(x)

Step-by-step explanation:

We have y= 6x-5

Then, we take x depending on y like:

6x-5=y

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6x/6=y/6 + 5/6

x= y/6+ 5/6

Now, we replace x by the function g(x) and y by the variable x, then we have

g(x)= (1/6)x+5/6 is the inverse function of f(x).

Hope that you understand.

6 0
3 years ago
Find the area of the part of the paraboloid z = 9 - x^2 - y^2 that lies above the xy-plane.
svetoff [14.1K]

Parameterize this surface (call it S) by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(9-u^2)\,\vec k

with 0\le u\le3 and 0\le v\le2\pi. Take the normal vector to S to be

\vec r_u\times\vec r_v=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k

Then the area of S is

\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

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3 0
3 years ago
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