Answer:
112.569 ( D )
Step-by-step explanation:
Applying the estimated Regression Equation
y = b1X1 + b2X2 + a
b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884
b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925
a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252
y = 0.939X1 + 0.309X2 + 31.733
For x1 ( age ) =39, and x2(weight) =143
y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569
where
Sum of X1 = 981
Sum of X2 = 3102
Sum of Y = 2388
Mean X1 = 61.3125
Mean X2 = 193.875
Mean Y = 149.25
attached is the Tabular calculation of the required values needed for estimated regression equation
With some simple rearrangement, we can rewrite the numerator as

Then factorizing the difference of squares,
, we end up with

Answer:
A ≈ 25.1 cm²
Step-by-step explanation:
the area (A) of the sector is calculated as
A = area of circle × fraction of circle
= πr² × 
= π × 6² × 
= 36π × 
= 18 × 
= 2 × 4π
= 8π
≈ 25.1 cm² ( to the nearest tenth )
1. The problem says that the television has a rectangular shape. So, the formula for caculate the area of a rectangle is:
A=LxW
"A" is the area of the rectangle (A=3456 inches²).
"L" is the the length of the rectangle.
"W" is the width of the rectangle.
2. The <span>width of the screen is 24 inches longer than the length. This can be expressed as below:
W=24+L
3. Then, you must substitute </span>W=24+L into the formula A=LxW:
<span>
</span>A=LxW
<span> 3456=L(24+L)
3456=24L+L</span>²
<span>
4. The quadratic equation is:
L</span>²+24L-3456=0
5. When you solve the quadratic equation, you obtain:
L=48 inches
6. Finally, you must substitute the value of the length, into W=24+L:
W=24+L
W=24+48
W=72 inches
7. Therefore, the dimensions of the screen are:
L=48 inches
W=72 inches<span> </span>
It’s the last one. (X+2)2+(x+372-1/2)