Can someone help me with this plz? Plz show ur work .... A local high school collected $1590 from 321 people who attended a foot
1 answer:
To solve this problem we can use system of equations.
First equation can be
321=x+y
where x - ppl between 4-17 and y - adult
second equation can be as follows
1590=6*y+4*x
So we have
From first equation we get value of x in times of y
x=321-y
Now we can substitute it into second eq.
1590=6y+4(321-y)
now simply if
1590=6y+1284-4y /-1284 both sides
306=2y /:2 divide both sides by 2
y=153
Now we can back substitude
x=321-153
x=168
So we get result
First equation can be
321=x+y
where x - ppl between 4-17 and y - adult
second equation can be as follows
1590=6*y+4*x
So we have
From first equation we get value of x in times of y
x=321-y
Now we can substitute it into second eq.
1590=6y+4(321-y)
now simply if
1590=6y+1284-4y /-1284 both sides
306=2y /:2 divide both sides by 2
y=153
Now we can back substitude
x=321-153
x=168
So we get result
You might be interested in
Answer:
b) 24
Step-by-step explanation:
We solve building the Venn's diagram of these sets.
We have that n(S) is the number of succesful students in a classroom.
n(F) is the number of freshmen student in that classroom.
We have that:
In which n(s) are those who are succeful but not freshmen and are those who are succesful and freshmen.
By the same logic, we also have that:
The union is:
In which
So
So the correct answer is:
b) 24