Question

Can someone help me with this plz? Plz show ur work .... A local high school collected $1590 from 321 people who attended a football game. The price of each adult admission is $6. People between the ages of 4-17 paid a children admission rate of $4. How many adult tickets and child tickets were sold that day?

Answer 1

To solve this problem we can use system of equations.
First equation can be
321=x+y 
where x - ppl between 4-17 and y - adult
second equation can be as follows
1590=6*y+4*x
So we have
$\left \{ {{321=x+y} \atop {1590=6y+4x}} \right.$
From first equation we get value of x in times of y
x=321-y
Now we can substitute it into second eq.
1590=6y+4(321-y) 
now simply if
1590=6y+1284-4y            /-1284 both sides
306=2y                /:2 divide both sides by 2
y=153 
Now we can back substitude
x=321-153
x=168
So we get result
$\left \{ {{y=153 - adult} \atop {x=168 - kids}} \right.$