Well lets try using negatives and positives, negatives for underground positives for above. -6 + 14 = 8 then 8 - 11 = -3. When Herman finally stops climbing he is 3 feet below ground level.
Remember:
a^m * a^n=a^(m+n)
a^-m=1/a^m
8³ x 8⁻⁵=8³⁻⁵=8⁻²=1/8²=1/64<1
Answer: the student is not correct, because 1/64<1, and 8³ x 8⁻⁵=1/64.
If tan (x)+pi/6=0
thn
tan (x)=-pi/6
take atan of both sides
x=atan (-pi/6)
x= -0.4823 rad
= -27.636 deg
The statement "<span>The rate of change of y with respect to x is inversely proportional to y^4" can be written mathematically as dy/dx = k/y^4
To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A
![y= \sqrt[5]{Bx+C}](https://tex.z-dn.net/?f=y%3D%20%5Csqrt%5B5%5D%7BBx%2BC%7D%20)
</span>