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tamaranim1 [39]

3 years ago

8

Solve for x: 4 over 5 x + 4 over 3 = 2x x = __________________ Write your answer as an improper fraction in simplest form. Use t

he "/" symbol for the fraction bar.

2 answers:

MissTica3 years ago

5 0

Answer:

x= 10/9, or 10 over 9

Step-by-step explanation:

hammer [34]3 years ago

4 0

Let's solve your equation step-by-step.

4/5x+4/3=2x

Step 1: Subtract 2x from both sides.

4/5x+4/3−2x=2x−2x

−6/5x+4/3=0

Step 2: Subtract 4/3 from both sides.

−6/5x+4/3−4/3=0−4/3

−6/5x=−4/3

Step 3: Multiply both sides by 5/(-6).

(5/−6)*(−6/5x)=(5/−6)*(−4/3)

x=10/9

Answer:

x=10/9

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3 years ago

Ace Bike Rentals rents bikes for $28 per day Renters can keep the bike for 8 hours Bart’s Bikes rents bikes for $30 per day Rent

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4 0

3 years ago

Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

GrogVix [38]

<u>QUESTION 1</u>

The given system of equation is

$y=x-6...eqn1$

and

$3x+2y=8...eqn2$

Let us substitute equation (1) into equation (2) to get,

$3x+2(x-6)=8$

We expand the bracket to get,

$3x+2x-12=8$

We simplify to get.

$5x-12=8$

We group like terms to get

$5x=8+12$

$\Rightarrow 5x=20$

$\Rightarrow x=4$

We now substitute $x=4$ in to equation (1) to obtain,

$y=4-6=-2$

The correct answer is option A.

<u>QUESTION 2</u>

The given system of equations is

$y-x=9...eqn1$

and

$10+2x=-2y...eqn2$

We make y the subject in equation (2) to get,

$y=-x-5..eqn3$

We put equation (3) into equation (1) to obtain,

$-x-5-x=9$

We group like terms to get,

$-x-x=9+5$

This implies that,

$-2x=14$

We divide through by $-2$ to get,

$x=-7$

Hence the x-coordinate is $-7$

<u>QUESTION 3</u>

The given system is

$y=3x-1..eqn1$

and

$x-y=-9...eqn2$

We make $x$ the subject in equation (2) to get,

$x=y-9...eqn3$

We put equation (3) into equation (1) to obtain,

$y=3(y-9)-1$

We expand the bracket to get,

$y=3y-27-1$

Group like terms to get,

$y-3y=-27-1$

We simplify to get;

$-2y=-28$

This implies that,

$y=14$

Therefore the y-coordinate is 14.

4 0

4 years ago

Read 2 more answers

Let's find2. 1+5 3First write the addition with a common denominator.Then add.12— +51-4-13Х5

emmasim [6.3K]

Answer: $\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$ Explanation:

The given addition exercise is:

$\frac{2}{5}+\frac{1}{3}$

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

$\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}$

Multiply 1/3 by 5/5

$\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}$

The addition becomes

$\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

Therefore, we can fill in the vacant boxes as shown below:

$\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

4 0

1 year ago

A math teacher keeps her wall-sized graph paper in a box shaped like a triangular prism. The triangular face of the prism has a

yaroslaw [1]

(24 × 17 × 130\2)

24 × 17 = 408 x 130 = 53,040 / 2 = 26,520
So the volume of this box is

C= 26,520 cm^3

6 0

2 years ago