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Murrr4er [49]
3 years ago
8

the elves were working when the head elf came in and there was only 2 weeks left until christmas. what percentage of the month w

as left before christmas?
Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

45 %

Step-by-step explanation:

Time left until Christmas = 2 weeks

                                         = 2 * 7 days                [since 1 week = 7 days]

                                         = 14 days

Number of days in December = 31

Percentage of the month left before Christmas = \frac{Time left until Christmas}{Number of days in December} * 100

= \frac{14}{31} * 100

= 0.45 * 100

= 45 %

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Ira Lisetskai [31]
It will be a horizontal line at y=7 and shaded above. If you have pictures of the graph I can show which one it would be.
7 0
3 years ago
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On a flight from New York to London, an airplane travels at a constant speed. An equation relating the distance traveled in mile
lions [1.4K]

Complete question :

On a flight New York to London an airplane travels at a constant speed. An equation relating the distance traveled in miles d to the number of hours flying t is t= 1/500d. How long will it take the airplane to travel 800 miles?

Answer:

1.6 hours

Step-by-step explanation:

Given the function :

Time t taken for flying distance d is given by:

t = 1/500 * d

Tine taken to fly 800 miles;

d = 800 miles

t = 1/500 * (800)

t = 800 / 500

t = 1.6

Hence, time t = 1.6 hours

3 0
3 years ago
Suppose that contamination particle size (in micrometers) canbe modeled as
asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1

a) probability density function.

\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1

Thus, it is a probability density function.

b) cumulative distribution function.

P(X

c) mean of the distribution

\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2

d) probability that the size of random particle will be less than 5 micrometers

P(X

4 0
2 years ago
If p(x) = x^2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? 5(x – 1) – x^2 – 1 (5x – 1) – (x^2 – 1) (x^2 –
Murrr4er [49]
P(x) = x^2 - 1
q(x) = 5(x - 1)
(p - q)(x) = p(x) - q(x) = (x^2 - 1) - 5(x - 1)
8 0
3 years ago
The population of a local species of beetle can be found using an infinite geometric series where a1 = 880 and the common ratio
nasty-shy [4]
<span>Data:

infinite geometric series

A1 = 880

r = 1 / 4

The sum of a geometric series  in sigma notation is:

  n              1 - r^n
 ∑ Ai = A ----------- ; where A = A1
i = 1             1-r

 When | r | < 1 the infinite sum exists and is equal to</span><span><span>:

  ∞               A
 ∑ Ai =   ---------- ; where A = A1
i = 1          1 - r</span>

So, in this case</span><span><span>:

  ∞               880
 ∑ Ai =    -------------- = 4 * 880 / 3 = 3520 /3 = 1173 + 1/3
i = 1         1 - (1/4)</span>  </span>

Answer: 1173 and 1/3
6 0
3 years ago
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