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TEA [102]
3 years ago
6

I’m confused on this one

Mathematics
1 answer:
andriy [413]3 years ago
6 0

The point-slope form of the equation of a line is

y - y_1 = m(x - x_1)

where (x1, y1) is a point on the line, and m is the slope of the line.

y - 3 = \dfrac{5}{3}(x - 0)

y - 3 = \dfrac{5}{3}x

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What is a solution of the inequality shown below? -1 + x < -10​
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Multiply each equation by a constant that would help to eliminate the y terms.
Zinaida [17]

Answer:

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

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Step-by-step explanation:

Given:

2x-5y=-21         ......................Equation ( 1 )

3x-3y=-18         ......................Equation ( 2 )

To Find:

Expression after multiplying to eliminate y term,

Solution:

So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5,  such that equations  becomes

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-5(3x-3y)=-5\times -18\\\\-15x+15y=90  .....( 2 )

so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

Negative 15 x + 15 y = 90

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