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3 years ago

I’m confused on this one

Mathematics

1 answer:

andriy [413]3 years ago

6 0

The point-slope form of the equation of a line is

$y - y_1 = m(x - x_1)$

where (x1, y1) is a point on the line, and m is the slope of the line.

$y - 3 = \dfrac{5}{3}(x - 0)$

$y - 3 = \dfrac{5}{3}x$

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Find the distance between points P(2, 2) and Q(7, 4) to the nearest tenth.

kirill115 [55]

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points P(2, 2) ans Q(7, 4). Substitute:

$|PQ|=\sqrt{(7-2)^2+(4-2)^2}=\sqrt{5^2+2^2}=\sqrt{25+4}=\sqrt{29}\approx5.4$

<h3>Answer: PQ = 5.4</h3>

8 0

3 years ago

it costs $5.50 per hour to rent a pair of ice skates, for up to 2 hours. After 2 hours, the rental cost per hour decreases to $2

laila [671]

$5.50 x 2 is $11.00
$2.50 x 2 is $5.00
$11 plus $5 is $16
it costs $16 to rent a pair of skates for 4 hours

6 0

3 years ago

In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree

Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

$\cos A=\dfrac{b^2+c^2-a^2}{2bc}$

Using Law of Cosines in triangle OPQ, we get

$\cos P=\dfrac{o^2+q^2-p^2}{2oq}$

$\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}$

$\cos P=\dfrac{490000+384400-705600}{868000}$

$\cos P=\dfrac{168800}{868000}$

On further simplification, we get

$\cos P=0.19447$

$P=\cos^{-1}(0.19447)$

$P=78.786236$

$P\approx 79$

Therefore, the measure of angle P is 79 degrees.

8 0

3 years ago

Read 2 more answers

shtirl [24]

A grocery store sells a 6-pack of bottled water for $3.79, a 9-pack for$4.50, and a 12-pack for $6.89. which package costs the least per bottle?

6 0

3 years ago

Can you please answer the question? Thank you so much.

pychu [463]

Answer:

bruh

Step-by-step explanation:

4 0

3 years ago