4 years ago

I need help please ...

Mathematics

1 answer:

Simora [160]4 years ago

6 0

I'm pretty sure it is 32

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-2x + 3y = 18. x = -y + 1

Bezzdna [24]

Answer:

D. X=-3, y=4

Step-by-step explanation:

-2x+3y=18 equation 1

x=-y+1 equation 2

-2(-y+1)+3y=18 replace x value of equation 2 into equation 1

2y-2+3y=18

5y=20

y=4

solve for x by replacing y value into either equation.

x=-y+1

x=-4+1

x=-3

8 0

3 years ago

A target has a bull’s-eye with a diameter of 2 inches. the outer ring is 1 inch wide. what is the area of the outer ring?

andrew11 [14]

The diameter of the outer ring will be 4 inches since it extends one inch beyond the bull's eye from either side. See the attached image for clarification.

The area of the outer ring can be expressed as:
$Area_{outerring} = Area_{outercircle} - Area_{bullseye}$
This is because we need to take into account of the space taken up by the bullseye.

Now we set up our equation:
$Area_{outerring} = \pi r^{2}_{outercircle} - \pi r^{2}_{bullseye}$

Now plug and solve:
$Area_{outerring} = \pi 2^{2} - \pi 1^{2}$
$Area_{outerring} = 4\pi - \pi$
$Area_{outerring} = 9.42477796$