Question

Janet has three times as many dimes as nickels and twice as many quarters as nickels. If she has $3.40 in all, how many nickels, dimes, and quarters does she have?
If n represents the number of nickels Janet has, which of the following equations could be used to solve the problem?

5n + 10n + 25n = 340
n + 3n + 2n = 340
5n + 30n + 50n = 340

Answer 1

Good morning, your answer would be 5n + 10n + 25n = 340.

Answer 2

Answer:

$5n+30n+50n= 340$

Step-by-step explanation:

Janet has three times as many dimes as nickels and twice as many quarters as nickels.she has $3.40 in a.

Let n be the number of nickels

d be the number of dimes and q be the number of quarts

1 nickel = 5 cents

1 dime = 10 cents

1 quarter = 25 cents

Convert the dollars into cents by multiplying by 100

3.40 dollars = 3.40 times 100 is 340 cents

Janet has three times as many dimes as nickels and twice as many quarters as nickels

dimes is 3 times of nickels

$d=3n$

quarts is twice as many as nickels

$q=2n$

Now we frame equation

5 nickels plus 10 dimes plus 25 quarts is total 340 cents

$5n+10d+25q= 340$

Replace d  and q

$5n+10(3n)+25(2n)= 340$

$5n+30n+50n= 340$