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2 years ago

Please answer accurately and show work if you can

Mathematics

1 answer:

scoundrel [369]2 years ago

7 0

Answer:

A. a - 3 ≤ -5

Step-by-step explanation:

Move all terms with a to the right side of the inequality

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Mr. Jones' other friend Ms. O'Neill has "x" meters of fencing, what is the maximum area in square meters she can have?

Alexus [3.1K]

Answer:

$Max\ Area = \frac{x^2}{16}$

Step-by-step explanation:

Given

$P = x$ ---- the perimeter of fencing

Required

The maximum area

Let

$L \to Length$

$W \to Width$

So, we have:

$P = 2(L + W)$

This gives:

$2(L + W) = x$

Divide by 2

$L + W = \frac{x}{2}$

Make L the subject

$L = \frac{x}{2} - W$

The area (A) of the fence is:

$A = L * W$

Substitute $L = \frac{x}{2} - W$

$A = (\frac{x}{2} - W) * W$

Open bracket

$A = \frac{x}{2}W - W^2$

Differentiate with respect to W

$A' = \frac{x}{2} - 2W$

Set to 0

$\frac{x}{2} - 2W = 0$

Solve for 2W

$2W = \frac{x}{2}$

Solve for W

$W = \frac{x}{4}$

Recall that:

$L = \frac{x}{2} - W$

$L = \frac{x}{2} - \frac{x}{4}$

$L = \frac{2x- x}{4}$

$L = \frac{x}{4}$

So, the maximum area is:

$A = L * W$

$A = \frac{x}{4}*\frac{x}{4}$

$Max\ Area = \frac{x^2}{16}$

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2 years ago

If in circle A is 60°, what is m∠BDC?

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Step-by-step explanation:

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