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- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x


so

and

so

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1
4rt33 or 4 times the square root of 33
4 = the square root of sixteen, so the square root of 16 times the square root of 33 = the square root of 628
Area of the shaded region = area of big square minus area of little square.
Here is the set up:
Let A_s = area of shaded region.
A_s = (2x + 2)(3x - 4) - [(x - 3)(x - 6)]
Take it from here.
Answer:
w2+x6
Step-by-step explanation:
w+w+x+x+x+x+x+x will equal to w2+x6