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Anon25 [30]
3 years ago
14

Which statement must be true to prove j || k?

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

The answer is b. angle 6 must be equal to angle 4.

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Find the specified term of the following geometric sequences.
lidiya [134]

Answer:

7374

0.

Step-by-step explanation:

a^r = a1 * r^(n-1)

So, the terms are:

2*(3)^(8-1) = 4374

and

0*(1/2)^-1/2 = 0

3 0
1 year ago
What is the expanded form of 8.517
Dmitrij [34]
8 + 0.500 + 0.01 + 0.007
3 0
3 years ago
Read 2 more answers
I don’t know how to solve things like this
EleoNora [17]
To do this problem you need to find angle adc which is a part of angle BDA. angle BDA is 90 degrees so the 2 parts must add up to 90 degrees so you set up the problem like this
-2x + 144 - 3x +51 =90
then you combine like terms
-5x +195 = 90
then you subtract 195 from 90
-5x = -105
then you divide -5 by -5 and -105 by -5 and get
x=21
then you plug x in and get your angle measure
-3(21) +51
then you get the angle measure as 114 degrees.
8 0
3 years ago
What two numbers add to make twenty and have a difference of four?
Serggg [28]
Yes, you are correct.

The two numbers you add to make twenty and have a difference of four are 12 and 8.
5 0
3 years ago
Read 2 more answers
Which of the following points lies on the circle whose center is at the origin and whose radius is 13?
Alexxandr [17]

any point that is on the circle will  have a distance of "radius" units, namely 13 units, since the radius is just that.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{origin}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})}\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{12})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(-5-0)^2+(12-0)^2}\implies d=\sqrt{(-5)^2+12^2} \\\\\\ d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13

8 0
3 years ago
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