Answer:
Step-by-step explanation:
57.6
Multiply the bracket by 5
I used PEMDAS
P= parenthesis
E= exponents
M=multiplication
D= division
A= addition
S= subtraction
7r+2= 5(r-4)
7r+2= 5r-20
Move 5r to the left hand side . Positive 5r changes to negative 5r
7r-5r+2= 5r-5r-20
2r+2=- 20
2r+2-2= -20-2
Move positive 2 to the right hand side. Changes to negative -2
2r+2-2= -20-2
2r= -22
Divide by 2 for 2r and -22
2r/2= -22/2
r= -11
Answer is r= -11
Answer:
1400
Step-by-step explanation:
Because
7 x 2 = 14
Then add on the two zeroes at the end
1400
Answer:
The mistake she made was ; She didn't change the sign when subtracting -3/4 from both sides
She wrote 5/4+3/4 instead of 5/4-3/4
Step-by-step explanation:
Correct solution:
Subtract-3/4 from both sides
Simplify
The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.
If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.
The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.
The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.
This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.