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4 years ago

Dividing by 3 is the same as multiplying by 1/3. True or false

Mathematics

2 answers:

saul85 [17]4 years ago

6 0

Answer:

Step-by-step explanation:no different

NikAS [45]4 years ago

5 0

Answer:

this is true!

Step-by-step explanation:

its true lnfao.

You might be interested in

Adam has 10 blocks numbered 1 through 10. Which describes the probability of randomly choosing a block that has an even number?

Licemer1 [7]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given that:

10 number of blocks which have numbers from 1 through 10.

To find:

Probability of randomly choosing a block that has an even number.

Solution:

The given set of numbers is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

There are a total of 5 Even numbers are {2, 4, 6, 8, 10}.

And There are a total of 5 Odd number are {1, 3, 5, 7, 9}.

Formula for probability of an event <em>E</em> can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, Event <em>E </em>is randomly choosing an even number.

Number of favorable cases = 5

Total number of cases = 10

Therefore, the required probability is:

$P(E) = \dfrac{5}{10}\\\Rightarrow P(E) = \dfrac{1}{2}$

3 0

3 years ago

In 6n + 8N is best described as

disa [49]

Answer:

6n + 8n would be described as a variable because its a letter.

7 0

3 years ago

Write as a fraction in simplest form.

seropon [69]

Answer:

2/4=1/2

3/6=1/2

4/16=1/4

7 0

3 years ago

Original Price Percent of Discount original $112 percent discount 32% sale price ?

lina2011 [118]

76.16 is the answer

pls mark me the brainliest

3 0

3 years ago

A random sample of 101 lightning flashes in a certain region resulted in a sample average radar echo duration of 0.81 sec and a

Masteriza [31]

Answer:

The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.

Step-by-step explanation:

We have the sample standard deviation, so we use the student t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.6259

The margin of error is:

M = T*s = 2.6259*0.45 = 1.18

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.81 - 1.18. Answer in seconds cannot be negative, so we use 0 sec.

The upper end of the interval is the sample mean added to M. So it is 0.81 + 1.18 = 1.99 sec

The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.

6 0

3 years ago