The ordered pair which makes both inequalities true is (-2, 2).
It is given that inequalities are
y < -x + 1 and y > x
For y < -x + 1
Substituting every ordered pair,
1) (-3, 5)
⇒ 5 < - (-3) + 1
⇒ 5 < 3 + 1
⇒ 5 < 4 is false
2) (-2, 2)
⇒ 2 < -(-2) + 1
⇒ 2 < 2 + 1
⇒ 2 < 3 is true
3) (-1, -3)
⇒ -3 < - (-1) + 1
⇒ -3 < 1 + 1
⇒ -3 < 2 is true
4) (0, -1)
⇒ -1 < -0 + 1
⇒ -1 < 1 is true
Now , for y > x
1) (-3, 5)
⇒ 5 > -3 is true
2) (-2, 2)
⇒ 2 > -2 is true
3) (-1, -3)
⇒ -3 > -1 is false
4) (0, -1)
⇒ -1 > 0 is false
Therefore ,the ordered pair which makes both inequalities true is (-2, 2).
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Let's solve your equation step-by-step.<span><span>−<span>4<span>(<span>r+2</span>)</span></span></span>=<span>4<span>(<span>2−<span>4r</span></span>)</span></span></span>Step 1: Simplify both sides of the equation.<span><span>−<span>4<span>(<span>r+2</span>)</span></span></span>=<span>4<span>(<span>2−<span>4r</span></span>)</span></span></span><span>Simplify</span><span><span><span><span>(<span>−4</span>)</span><span>(r)</span></span>+<span><span>(<span>−4</span>)</span><span>(2)</span></span></span>=<span><span><span>(4)</span><span>(2)</span></span>+<span><span>(4)</span><span>(<span>−<span>4r</span></span>)</span></span></span></span>(Distribute)<span><span><span><span>−<span>4r</span></span>+</span>−8</span>=<span><span>8+</span>−<span>16r</span></span></span><span><span><span>−<span>4r</span></span>−8</span>=<span><span>−<span>16r</span></span>+8</span></span>Step 2: Add 16r to both sides.<span><span><span><span>−<span>4r</span></span>−8</span>+<span>16r</span></span>=<span><span><span>−<span>16r</span></span>+8</span>+<span>16r</span></span></span><span><span><span>12r</span>−8</span>=8</span>Step 3: Add 8 to both sides.<span><span><span><span>12r</span>−8</span>+8</span>=<span>8+8</span></span><span><span>12r</span>=16</span>Step 4: Divide both sides by 12.<span><span><span>12r</span>12</span>=<span>1612</span></span><span>r=<span>43</span></span>Answer:<span>r=<span>4<span>3</span></span></span>
Answer:
Step-by-step explanation:
Given the original coordinate as C (-6, 9) and new coordinates after dilation as C' (-2, 3), we can see that the value of the new coordinates has reduces by a factor. Let the factor be k
For the x coordinates:
C' = kC
x' = kx
-2 = k(-6)
-2 = -6k
Divide both sides by -6
k = -2/-6
k = 1/3
For the y-coordinates:
y' = ky
3 = 9k
Divide both sides by 9:
3/9 = 9k/9
1/3 = k
k = 1/3
Hence the scale factor of the dilation is 1/3
Answer:
it wont let me write the graph
Step-by-step explanation:
