1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anon25 [30]
3 years ago
9

Use absolute value to express the distance between −10 and 16 on the number line.Use absolute value to express the distance betw

een −10 and 16 on the number line.Use absolute value to express the distance between −10 and 16 on the number line.Use absolute value to express the distance between −10 and 16 on the number line.
Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

=∣∣−26∣∣=26

Step-by-step explanation:

∣∣x−y∣∣=?

x =  

-10

y =  

16

Answer:

∣∣x−y∣∣=26

Solution:

∣∣x−y∣∣

=∣∣(−10)−16∣∣

=∣∣−10−16∣∣

You might be interested in
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\

\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
3 years ago
Paul Havlik promised his grandson Jamie that he would give him $7,100 7 years from today for graduating from high school. Assume
Dominik [7]

Answer:

\large \boxed{\$4100.07}

Step-by-step explanation:

The formula for the future value (FV) of an investment earning compound interest is

FV = PV \left (1 + \frac{r}{n} \right )^{nt}

where

PV = the present value (PV) of the money invested

  r = the annual interest rate expressed as a decimal fraction

  t = the time in years

 n = the number of compounding periods per year

Data:

FV = $7100

  r =  8 % = 0.08

  t = 7 yr

 n = 2

Calculation:

\begin{array}{rcl}\\7100& =& PV \left (1 + \dfrac{0.08}{2} \right )^{2 \times 7}\\\\& =& PV (1 + 0.04)^{14}\\\\& =&PV (1.04)^{14}\\& =& PV(1.731676)\\PV& =& \dfrac{7100}{1.731676}\\\\& =& \mathbf{4100.07}\\\end{array}\\\text{The present value of the money is $\large \boxed{\mathbf{\$4100.07}}$}

4 0
3 years ago
For Howards science experiment he needs 69 blocks that each have a mass of 0.5 kilograms. Is the total mass of the blocks 3.45 k
Andreas93 [3]
34.5kg.
Just take 69 blocks and times by 0.5
6 0
3 years ago
The number of days in a month is measured in ones
krok68 [10]
The synodic month, or complete cycle of phases of the Moon as seen from Earth, averages 29.530588 mean solar days in length (i.e., 29 days 12 hours 44 minutes 3 seconds); because of perturbations in the Moon’s orbit, the lengths of all astronomical months vary slightly. The sidereal month is the time needed for the Moon to return to the same place against the background of the stars, 27.321661 days (i.e., 27 days 7 hours 43 minutes 12 seconds)
4 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.
natima [27]
The answer for coordinates of M is (-2/5, -4/5), and the coordinates of N is (1/5, 1). Hope it help!
5 0
3 years ago
Other questions:
  • How would I set up this problem?
    15·1 answer
  • Compare the quantity in Column A with the quantity in column B. Choose the best answer.
    13·2 answers
  • A snail moves 1/40 of a mile in 3/4 of an hour. If the snail continues at this pace, how far, in miles, does it move in one hour
    7·2 answers
  • What is the solution to the equation below?<br> log7+log(x-4)= 1
    8·1 answer
  • ILL MARK AS BRAINLIST IF U GET IT RIGHT it’s khan
    5·1 answer
  • I need this question answered fast ;c
    7·2 answers
  • Which of the following geometric series converges?
    6·1 answer
  • A bolt has 6 1/2 turns per inch how many turns would be in 2 1/2 inches of threads
    8·1 answer
  • What is the function of the tentacles of a cnidarian?
    5·1 answer
  • The total cost for one year at the state university is $22,500. a student has the following help in covering the costs of school
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!