Question

Find the value of x if b is the midpoint of AC, AB=3-2x, BC=x-12

Answer 1

ANSWER:

The value of x if b is the midpoint of AC, AB=3 - 2x, BC = x - 12 is 5

SOLUTION:    

Given, B is the midpoint of points A and C

And given the distance values of AB and BC

i.e. AB = 3 – 2x and BC = x -12

we need to find the value of x  

now, as B is the midpoint of A and C  

Distance between A and B equals to Distance between B and C . So we get,

AB = BC

3 – 2x = x – 12

3 – 2x – (x – 12) = 0

3 – 2x –x +12 = 0

3 -3x + 12 = 0

-3x +15 = 0

-3x = -15

3x = 15

x = $\frac{15}{3}$

x = 5

Hence the value of x is 5.

Answer 2

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Answer:

5 = x

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Step-by-step explanation:

AB ≅ BC (because median cuts a line segment into two equal (congruent ≅) parts

Set up your equation now:

3 - 2x = x - 12

3 + 12 = 2x + x

15 = 3x

15/3 = x

5 = x

Step-by-step explanation: