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Wittaler [7]
3 years ago
13

What's the equation to solve this? Can't remember!

Mathematics
1 answer:
Lerok [7]3 years ago
7 0
Arc SCD is two times of angle SED, so arc SCD is 8x+22. Now set 8x+22, 5x-8, and 11x+10 to 360 and solve for x
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Susan wants to compete in a 3.75-mile race.She wants to finish the race in 25.5 minutes. What pace does Susan need to keep per m
ira [324]
25,5 minutes=25,5/60 hours=0,425 hours

3,75/0,425 miles/hour =8,8235≈8,82 miles/hour
3 0
3 years ago
A boy leaves on a bicycle trip at the rate of 8 mph. One hour later the father, realizing that his son forgot his camping gear,
Inessa05 [86]
<span>To catch him in 15 minutes the father must travel 32 miles per hour faster (since 1/4 hr * 32 mph = 8 miles)...
Thus the father must drive at 40 miles per hour. </span>
5 0
3 years ago
Read 2 more answers
Which statements about the hyperbola are true? Check all that apply.
max2010maxim [7]

Answer:

1.) There is a focus at (0,4)

4.) There is an asymptote with a slope of 4/3

These are the only 2 correct.

Step-by-step explanation:

Just took the quiz od edge!

4 0
4 years ago
Read 2 more answers
Please help I need help with my hw
olga2289 [7]

Answer:

a) 2.5 pounds of candy

b) 2.5 pounds of candy

    \frac{0.5}{1} :\frac{y}{5}

    y × 1 = 0.5 × 5

    y = 2.5

Step-by-step explanation:

1 = 5

1/2 = y or 0.5 = y

\frac{0.5}{1} :\frac{y}{5}

y × 1 = 0.5 × 5

y = 2.5

7 0
3 years ago
Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.
katrin [286]

x=5.38 . Correct option C)5.38

<u>Step-by-step explanation:</u>

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.  picture is attached  . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x

By Pythagoras Theorem ,

Hypotenuse^2=Perpendicular^2+base^2

⇒ x^2=(3.6)^2+(4)^2

⇒ x=\sqrt{(3.6)^2+(4)^2}

⇒ x=\sqrt{12.96+16}

⇒ x=\sqrt{28.96}

⇒ x=5.38

Therefore , x=5.38 . Correct option C)5.38

6 0
3 years ago
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