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katrin [286]
3 years ago
5

In multi-level inheritance one class inherits how many classes?

Computers and Technology
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

Only one class

Explanation:

The classes will inherit only from one class. This will continue as each class inherits only one class. There should not be any class that inherits from two or more classes or which have more than one subclass.

You might be interested in
Effective nonverbal communication can cause tension.<br><br> True or False
agasfer [191]

Explanation:

When your nonverbal signals match up with the words you're saying, they increase trust, clarity, and rapport. When they don't, they can generate tension, mistrust, and confusion.

4 0
3 years ago
Write a method called findNames that meets the following specs: It takes two arguments: a list of strings, allNames, and a strin
Anna11 [10]

Answer:

public class Solution {

   public static void main(String args[]) {

       String[] allNames = new String[]{"Bob Smith", "Elroy Jetson", "Christina Johnson", "Rachael Baker", "cHRis", "Chris Conly"};

       String searchString = "cHRis";

       

       findNames(allNames, searchString);

   }

   

   public static void findNames(String[] listOfName, String nameToFind){

       ArrayList<String> resultName = new ArrayList<String>();

       

       for(String name : listOfName){

           if (name.toLowerCase().contains(nameToFind.toLowerCase())){

               resultName.add(name);

           }

       }

       

       for(String result : resultName){

           System.out.println(result);

       }

   }

}

Explanation:

The class was created called Solution. The second line define the main function. Inside the main function; we initialized and assign an array called allNames to hold the list of all name. Then a String called searchString was also defined. The searchString is the string to search for in each element of allNames array. The two variables (allNames and searchString) are passed as argument to the findNames method when it is called.

The method findNames is defined and it accept two parameters, an array containing list of names and the name to search for.

Inside the findNames method, we initialized and assigned an ArrayList called resultName. The resultName variable is to hold list of element found that contain the searchString.

The first for-loop goes through the elements in the allNames array and compare it with the searchString. If any element is found containing the searchString; it is added to the resultName variable.

The second for-loop goes through the elements of the resultName array and output it. The output is empty if no element was found added to the resultName variable.

During comparison, the both string were converted to lower case before the comparison because same lowercase character does not equal same uppercase character. For instance 'A' is not same as 'a'.

8 0
3 years ago
Write an example method that overrides the operator to create a new book whose title is a concatenation of the titles of two boo
Anastasy [175]

next time m8 mmmmmdsaasd

5 0
3 years ago
Write a program that prompts the user for an integer, then asks the user to enter that many values. Store these values in an arr
Svetllana [295]

Answer:

//The Scanner class is imported to allow the program receive user input

import java.util.Scanner;

//The class Solution is defined

public class Solution {

   //The main method is defined here and signify the beginning of program execution

   public static void main(String args[]) {

       

       //Scanner object 'scan' is created to receive user input

       Scanner scan = new Scanner(System.in);

       //Prompt display to the user to enter size of array

       System.out.print("Enter the range of array: ");

       //User input is assigned to arraySize

       int arraySize = scan.nextInt();

       //userArray is initialized with arraySize as its size

       int[] userArray = new int[arraySize];

       

       //counter to count number of array element

       int count = 0;

       //while loop which continue executing till the user finish entering the array element

       while (count < arraySize){

           System.out.print("Enter each element of the array: ");

           userArray[count] = scan.nextInt();

           count++;

       }

       

       //A blank line is printed for clarity

       System.out.println();

       

       //for loop to print each element of the array on straight line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

       

       //A blank line is printed for clarity

       System.out.println();

       

       //for loop is use to reverse the array in-place

       for(int i=0; i<userArray.length/2; i++){

           int temp = userArray[i];

           userArray[i] = userArray[userArray.length -i -1];

           userArray[userArray.length -i -1] = temp;

       }

       

       //for loop to print each element of the reversed array on straight line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

     

   }

}

Explanation:

The program is commented to give detailed explanation.

The for-loop use in reversing the array works by first dividing the array into two half and exchanging the first half elements with the second half elements. The element from the first half is assigned to temp variable on each loop, then the element is replaced with the equivalent element from the second half. And the element from the second half is replaced with the value of temp.

3 0
3 years ago
This rights protected document cannot be opened because the rights management feature has been disabled on your machine by Polic
erastovalidia [21]

This rights protected document cannot be opened because the rights management feature has been disabled on your machine by Policy is known to be an error message.

<h3>What is the error message about?</h3>

The Error message above is known to be one that shows that  your IT department has made a group policy in one's company's Active Directory. It is known to be one that tends to disables the use of ADRMS (Rights Management Feature) in all to all users.

Note that in the case above, one need to ask your IT department to be able to disable or make changes to the group policy so that it will not apply to the users who are said to require access secured Microsoft Office documents in any of Ansarada Rooms.

Another option is to look at documents off the network with the use of a personal computer or a mobile phone.

Hence, This rights protected document cannot be opened because the rights management feature has been disabled on your machine by Policy is known to be an error message.

Learn more about  error message from

brainly.com/question/25671653

#SPJ1

4 0
2 years ago
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