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3 years ago

To assign the contents of one array to another, you must use ________.

Computers and Technology

1 answer:

iren [92.7K]3 years ago

8 0

Answer:

Option c is the correct answer for the above question.

Explanation:

The array is used to holds multiple variables and the assignment operator can assign only a single variable at a time. So if a user wants to assign the whole array value into other array value then he needs to follow the loop.
The loop iteration moves on equal to the size of the array. It is because the array value moves into another array in one by one. It means the single value can move in a single time. So the moving processor from one array to another array takes n times if the first array size is n.
The above question asked about the processor to move the element from one array to another and the processor is a loop because the loop can execute a single statement into n times. So the C option is correct while the other is not because--

Option 'a' states about one assignment operator which is used for the one value only.
Option b states about the equality operator which is used to compare two values at a time.
Option d states any of these but only option c is the correct answer.
Option 'e' states none of these but option c is the correct.

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gizmo_the_mogwai [7]

Answer: Emergency Operation Center (EOC)

Explanation:

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3 years ago

In the simulation, player 2 will always play according to the same strategy. The number of coins player 2 spends is based on wha

baherus [9]

The simulation, player 2 will always play according to the same strategy.

Method getPlayer2Move below is completed by assigning the correct value to result to be returned.

Explanation:

You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.

#include <bits/stdc++.h>

using namespace std;

bool getplayer2move(int x, int y, int n)

{

int dp[n + 1];

dp[0] = false;

dp[1] = true;

for (int i = 2; i <= n; i++) {

if (i - 1 >= 0 and !dp[i - 1])

dp[i] = true;

else if (i - x >= 0 and !dp[i - x])

dp[i] = true;

else if (i - y >= 0 and !dp[i - y])

dp[i] = true;

else

dp[i] = false;

}

return dp[n];

}

int main()

{

int x = 3, y = 4, n = 5;

if (findWinner(x, y, n))

cout << 'A';

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3 years ago

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andreev551 [17]

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3 years ago

Give a tight bound on the number of times the z = z + 1 statement is executed. i = 2 while ( i > 1 ) { i = floor(i/2) z = z +

Alinara [238K]

Answer:

zero ( 0) times.

Explanation:

In the code;

i = 2

while ( i > 2){

i = floor( i/2 );

z = z + 1;

}

the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.

But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.

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3 years ago

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makkiz [27]

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1 year ago