Answer:
The answer is cross-site scripting(XSS)attack.
Explanation:
Hope this helps!
Answer: Reusing software device has some economical challenges such as:
- Investment cost in reusing the device is considered as the extra cost.It might require some extra components for the working to become usable
- Requires skilled person who can develop and design the software to be used again.The creating and designing of new software design is comparatively easy but making the system reusable requires someone who has more designing skill who will be highly paid for the work
- Cost of writing and reading of the software can also be considered as the economical challenge as the reused system created is to be studied by some other organization members or sources not familiar with the functioning. .
Answer:
The answer is A
Explanation:
Basically, Shortest job first (SJF) is a scheduling policy that selects jobs on queue for execution within a short execution time.
From the definition of SJF above, it means that there are a lot of process on queue and the (SJF) job is to receive processes on queue to execute within a short execution time.
Therefore, if all the jobs or process arrives at the SJF at the same time, the SJF will forfeit one of its major purpose which is scheduling of jobs.
That will therefore not make Non-preemptive Shortest Job First (SJF) not function at its optimal point.
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}
Answer:
Explanation:
The answer is false
Because the 4 elements are shapes texture colour and size