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poizon [28]
3 years ago
8

An element has this information:

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

hydrogen

Explanation:

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Meera added blue copper sulphate crystals to some water in a beaker.
professor190 [17]

Answer:

The solid crystals disappeared

Explanation:

When a soluble solid solute is added to water, the solid solute disappears after a little while. The disappearance of this solute indicates that the solute has been dissolved in water.

In this case, blue copper sulphate crystals are added to water, the blue crystals disappear leaving only a blue solution. The disappearance of these blue copper sulphate crystals indicates that the substance has dissolved in water.

7 0
3 years ago
The equilibrium constant for the reaction 2x(g)+y(g)=2z(g) is 2.25 . what would be the concentration of y at equilibrium with 2
Troyanec [42]

[\text{Y}] \approx0.337\;\text{mol}\cdot\text{dm}^{-3} at equilibrium.

<h3>Explanation</h3>

Concentration for each of the species:

  • [\text{X}] = \dfrac{n}{V} = 2\; \text{mol}\cdot \text{dm}^{-3};
  • [\text{Y}] = \dfrac{n}{V} = 0\; \text{mol}\cdot \text{dm}^{-3};
  • [\text{Z}] = \dfrac{n}{V} = 3\; \text{mol}\cdot \text{dm}^{-3}.

There was no Y to start with; its concentration could only have increased. Let the change in [\text{Y}] be +x \; \text{mol}\cdot \text{dm}^{-3}.

Make a \textbf{RICE} table.

Two moles of X will be produced and two moles of Z consumed for every one mole of Y produced. As a result, the <em>change</em> in [\text{X}] will be +2\;x \; \text{mol}\cdot \text{dm}^{-3} and the <em>change</em> in [\text{Z}] will be -2\;x \; \text{mol}\cdot \text{dm}^{-3}.

\begin{array}{l|ccccc}\textbf{R}\text{eaction}&2\; \text{X}\; (g) & + &\text{Y}\; (g) & \rightleftharpoons &2 \; \text{Z}\; (g)\\\textbf{I}\text{nitial Condition}\; (\text{mol}\cdot\text{dm}^{-3})& 2 & &0 & & 3 \\\textbf{C}\text{hange in Concentration}\; (\text{mol}\cdot\text{dm}^{-3})\;& +2\;x & &+x &&-2\;x\\\textbf{E}\text{quilibrium Condition}\; (\text{mol}\cdot\text{dm}^{-3})& & &&&\end{array}.

Add the value in the C row to the I row:

\begin{array}{l|ccccc}\textbf{R}\text{eaction}&2\; \text{X}\; (g) & + &\text{Y}\; (g) & \rightleftharpoons &2 \; \text{Z}\; (g)\\\textbf{I}\text{nitial Condition}\; (\text{mol}\cdot\text{dm}^{-3})& 2 & &0 & & 3 \\\textbf{C}\text{hange in Concentration}\; (\text{mol}\cdot\text{dm}^{-3})\;& +2\;x & &+x &&-2\;x\\\textbf{E}\text{quilibrium Condition}\; (\text{mol}\cdot\text{dm}^{-3})& 2 + 2\;x & &x&&3-2\;x\end{array}.

What's the equation of K_c for this reaction? Raise the concentration of each species to its coefficient. Products go to the numerator and reactants are on the denominator.

K_c = \dfrac{[\text{Z}]^{2}}{[\text{X}]^{2} \cdot[\text{Y}]}.

K_c = 2.25. As a result,

\dfrac{[\text{Z}]^{2}}{[\text{X}]^{2} \cdot[\text{Y}]} = \dfrac{(3-2x)^{2}}{(2+2x)^{2} \cdot x} = K_c = 2.25.

(3-2\;x)^{2}= 2.25 \cdot(2+2\;x)^{2} \cdot x\\4\;x^{2} - 12 \;x + 9 = 2.25 \;(4\;x^{3} + 8 \;x^{2} + 4 \;x)\\4\;x^{2} - 12\;x + 9 = 9 \;x^{3} + 18\;x^{2} + 9\;x\\9\;x^{3} + 14\;x^{2} + 21\;x - 9 = 0.

The degree of this polynomial is three. Plot the equation y = 9\;x^{3} + 14\;x^{2} + 21\;x - 9 on a graph and look for any zeros. There's only one zero at x \approx 0.337. All three concentrations end up greater than zero.

Hence the equilibrium concentration of Y: 0.337\;\text{mol}\cdot\text{dm}^{-3}.

7 0
3 years ago
Hurry please quick summary
Nadya [2.5K]
I think that work is being done on the books because they are being moved to their proper location and they will be sorted properly rather than lying on a table. Without lifting or carrying, you could sort the books by their genre or title name on the bookshelf so it will be sorted much more efficiently.

I’m not sure if this is the answer you are looking for but I hope it helps :)
3 0
3 years ago
“How many moles of H2O are produced when 64.0 g C2H2 burn in oxygen?
Greeley [361]
I think the answer should be 44 mol H2O
64.0g C2H2 * 1 mol/26g C2H2*18 mol H2O/1 mol
8 0
3 years ago
2 ways friction is helpful and 2 ways it does not
iris [78.8K]

Benefits of friction.

1. Walking. Friction between the soles of our  shoes and the ground enables us to walk. The sole of the shoe is held to the ground through friction. This is what is termed as "grip" of the shoe. The more grip a shoes offers, the better and faster we can walk.

2. Writing. Writing using a pen requires friction. It is impossible to hold a pen in the hand without friction because it would slip out. Also the graphite point of the pencil would not make a mark on the paper without friction.

Drawbacks of friction

1. Drag. An aircraft taking off experiences significant friction between it and the air resulting in drag, so much fuel has to be used to  create energy to overcome the wind resistance.

2. Surface hindrance. Friction makes moving something heavy from  one part of a room to another very difficult. Sliding a large box across the flour takes a lot of energy due to friction between the box and the floor.


8 0
3 years ago
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