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3 years ago

Which of these compounds would you expect to be most soluble in water? ch3ch2cl ch3ch2ch2ch3 ch3ch2ch2f ch3ch2ch2oh?

Chemistry

2 answers:

Montano1993 [528]3 years ago

6 0

Answer : The compound that would be most soluble in water is CH3CH2CH2OH

Explanation :

Water is a polar solvent and can dissolve polar molecules. This is based on the principle "Like dissolves like".

Among the given molecules, CH3CH2CH2CH3 is a hydrocarbon known as butane. All hydrocarbons are non polar. Therefore this compound will not be soluble in water.

The remaining compounds are polar, but Ch3CH2CH2OH shows greater solubility in water owing to presence of hydrogen bonding.

Hydrogen bonding is a type of intermolecular force that gets formed when a compound has hydrogen atom directly attached to highly electro-negative N, F or O atom.

When CH3CH2CH2OH is dissolved in water, it forms hydrogen bonds with water molecules. Due to this hydrogen bonding, the molecule shows greater solubility.

Therefore CH3CH2CH2OH is the most soluble compound in water

Alja [10]3 years ago

3 0

Hello there!!! the answer should be D as it is the only one which has the required oxygen. I hope this helps!!!

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2 years ago

A frying pan needs a Teflon coating of 1.00 mm in thickness to cover an area of 36.0 square inches. How many ounces of Teflon ar

Otrada [13]

Answer:

m = 0.659 ounce

Explanation:

It is given that,

The thickness of a Teflon coating is, d = 1 mm

Area of the coating, A = 36 inch²

The density of Teflon, d = 0.805 g/mL

We need to find ounces of Teflon are needed.

Firstly, find the volume of the Teflon needed,

1 inch² = 6.4516 cm²

36 inch² = 232.258 cm²

Density,

$\rho=\dfrac{m}{V}$

V is volume of the Teflon needed, V = Ad

So,

$m=\rho V\\\\m=0.805\ g/cm^3\times 232.258\ cm^2 \times 0.1\ cm\\\\m=18.69\ g$

Also, 1 gram = 0.035274 ounce

18.69 gram = 0.659 ounce

So, 0.659 ounces of Teflon are needed.

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3 years ago

Compound that contains a terminal carbonyl?

malfutka [58]

Many compunds have a terminal carbonyl

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3 years ago

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Alexandra [31]

From what i can gather it looks like d

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