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Aleks [24]
3 years ago
6

Which of these compounds would you expect to be most soluble in water? ch3ch2cl ch3ch2ch2ch3 ch3ch2ch2f ch3ch2ch2oh?

Chemistry
2 answers:
Montano1993 [528]3 years ago
6 0

Answer : The compound that would be most soluble in water is CH3CH2CH2OH

Explanation :

Water is a polar solvent and can dissolve polar molecules. This is based on the principle "Like dissolves like".

Among the given molecules, CH3CH2CH2CH3 is a hydrocarbon known as butane. All hydrocarbons are non polar. Therefore this compound will not be soluble in water.

The remaining compounds are polar, but Ch3CH2CH2OH shows greater solubility in water owing to presence of hydrogen bonding.

Hydrogen bonding is a type of intermolecular force that gets formed when a compound has hydrogen atom directly attached to highly electro-negative N, F or O atom.

When CH3CH2CH2OH is dissolved in water, it forms hydrogen bonds with water molecules. Due to this hydrogen bonding, the molecule shows greater solubility.

Therefore CH3CH2CH2OH is the most soluble compound in water

Alja [10]3 years ago
3 0
Hello there!!! the answer should be D as it is the only one which has the required oxygen. I hope this helps!!!
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What information is need to calculate the percent composition of a compound?
Anestetic [448]

Answer:

Molecular formula

Explanation:

Molecular formula in the first place is required to understand which compound we have. We then should refer to the periodic table and find the molecular weight for each atom. Adding individual molecular weights together would yield the molar mass of a compound.

Then, dividing the total molar mass of a specific atom by the molar mass of a compound and converting into percentage will provide us with the percentage of that specific atom.

E. g., calculate the percent composition of water:

  • molecular formula is H_2O;
  • calculate its molar mass: [tex]M = 2M_H + M_O = 2\cdot 1.00784 g/mol + 16.00 g/mol = 18.016 g/mol;
  • find the percentage of hydrogen: [tex]\omega_H = \frac{2\cdot 1.00784 g/mol}{18.016 g/mol}\cdot 100 \% = 11.19 %;
  • find the percentage of oxygen: [tex]\omega_O = \frac{16.00 g/mol}{18.016 g/mol}\cdot 100 \% = 88.81 %.
8 0
3 years ago
In the reaction shown above , the?
matrenka [14]

Answer:

I think option (d) is right answer

8 0
3 years ago
You're provided a 0.50 M solution of HCl. How many moles of HCl are present in 25 ml of this solution? ​
ddd [48]

Answer:

0.0125 moles of HCl

Explanation:

(0.50 mol/L)(0.025 L) = 0.0125 moles of HCl

4 0
2 years ago
Which of the following is a true
Katarina [22]

❤️Hello!❤️ The answer is A. Energy can change from one form to another. Hope this helps! ↪️ Autumn ↩️

5 0
3 years ago
The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
krok68 [10]

Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = 2.83\times 10^{-3}

a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=3.96\times 10^{-3}min^{-1}

The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

6 0
3 years ago
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