Answer:- 27.7 grams of
are produced.
Solution:- The balanced equation is:

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.
Molar mass of
= 207.2+2(126.90) = 461 gram per mol
let's do the calculations for the grams of the product for the given grams of each of the reactant:

= 

= 
From above calculations, NaI gives least amount of
, so the answer is, 27.7 g of
are produced.
Answer: 7.025959200000001
Explanation:
Ba stays as Ba+2 and Cl stays as Cl-
4 total bonds if u have double,or triple then subtract from 4
The polarity of a water molecule
comes from the uneven distribution of electron density of hydrogen and oxygen
atom. The oxygen in the water molecule is more electronegative than the
hydrogen. Water has a partial positive charge near the hydrogen atom and a
partial negative charge near the oxygen atom. The result of this
electrostatic attraction results in the bond called hydrogen bond. Also,
because of this bond, it has the ability to dissolve most of the solutes due to
its polarity and bonding.